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Ierofanga [76]
3 years ago
13

Complete the chart below.

Chemistry
1 answer:
omeli [17]3 years ago
6 0

Answer:

Deformation of heat and pressure

Explanation:

It is deformation of heat and pressure because igneous rock is made by magma when it cools. After a long time and pressure, it will turn into sedimentary rock.

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To study a key fuel-cell reaction, a chemical engineer has 20.0-L tanks of H₂ and of O₂ and wants to use up both tanks to form 2
Lapatulllka [165]

the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

Given , to study a key fuel-cell reaction , a chemical engineer has 20.0L tanks of H2 and O2 and wants to use up both tanks to form 28.0mol of water at 23.8°C .

the reaction of the fuel cell is given by ,

H2(g) +1/2 O2 ( g) →H2O

Moles of H2 required = 28 mol

moles of O2 required = 14mol

Now according to van der waals equation ,

p= (nRT/ V-nb)  - an^2 / V^2

for H2 , a = 0.2453L^2bar /mol^2 , b= 0.02651L/mol

P for H2

= (28×0.0821×296.8/20-28×0.02651 ) -(0.2456 ×28×28/20×20)

P for H2 = 35.4291079-0.481376 = 34.9477319 atm

for O2 ,  a = 1.38L^2bar/mol^2 , b = 0.03186L/mol

P for O2 = (14×0.0821×296.8 /20-14×0.03186) - (1.382×14×14/20×20)

P for O2 = 17.4461807 - 0.67718 =16.7690007 atm

Hence , the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

Learn more about pressure here :

brainly.com/question/25965960

#SPJ4

6 0
1 year ago
7. List all of the variables that you controlled or kept the same.<br>Salt water​
satela [25.4K]

Answer:

Temperature is a common type of controlled variable. If a temperature is held constant during an experiment, it is controlled. Other examples of controlled variables could be an amount of light, using the same type of glassware, constant humidity, or duration of an experiment.

Explanation:

3 0
3 years ago
Why do some elements form double and triple bonds during bonding
jekas [21]

Explanation:

Elements need a total of eight electrons to gain stability and look like a noble gas. So, they sometimes need sharing of two, four or even six electrons to complete their octate. So, they form double and triple covalent bonds. One more  the reason is the  interaction between the p orbitals of the combining atoms. for example  A double bond, as in ethene H2C=CH2, arises from one combination of the s orbitals and one combination of the p_y orbitals.

4 0
3 years ago
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4
ddd [48]

Answer:

178.35g

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles ÷ volume

Based on the information provided in this question, molarity (M) of the solution = 1.50 M, volume = 725 mL = 725/1000 = 0.725L, n = ?

1.50 = n / 0.725

n = 1.50 × 0.725

n = 1.0875mol

Molar mass of Na3PO4

23(3) + 31 + 16(4)

= 69 + 31 + 64

= 164g/mol

Mole = mass ÷ molar mass

1.0875 = mass/164

mass = 178.35g

5 0
2 years ago
How many moles can be found in 1.5 x 10^24 atoms of Calcium?
mestny [16]
2.49 x 10^46 is the answer
5 0
3 years ago
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