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zmey [24]
3 years ago
5

A certain electromagnetic wave a wavelength of 415 nm. What is the frequency of the wave in hz?

Chemistry
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz

Explanation:

The wavelength of the electromagnetic wave, λ = 415 nm

The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s

Given that an electromagnetic wave is a periodic wave, we have;

The speed of the electromagnetic wave, c = f×λ

Where;

f = The frequency of the electromagnetic wave

Therefore, we have;

f = c/λ

From which we have;

f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz

The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz

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             %age Yield  =  51.45 %

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Step 1: Convert Kg into g

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Step 2: Find out Limiting reactant;

The Balance Chemical Equation is as follow;

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According to Equation,

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So,

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Solving for X,

                    X  =  (68500 g × 4 g) ÷ 28 g

                    X  =  9785 g of H₂

It shows 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.

Step 3: Calculate Theoretical Yield

According to equation,

            4 g (2 mol) H₂ reacts to produce  =  32 g (1 mol) Methanol

So,

                          8600 g H₂ will produce  =  X g of CH₃OH

Solving for X,

                    X  =  (8600 g × 32 g) ÷ 4 g

                     X =  68800 g of CH₃OH

Step 4: Calculate %age Yield

                     %age Yield  =  Actual Yield ÷ Theoretical Yield × 100

Putting Values,

                     %age Yield  =  3.54 × 10⁴ g ÷ 68800 g × 100

                     %age Yield  =  51.45 %


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