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Answer:The molar heat of vaporization of molten lead is 178.03 kJ/mol.
Explanation:
The molar heats of fusion of lead
...(1)
The molar heats of sublimation of lead
...(2)
Adding (1) and (2)
The molar heat of vaporization of molten lead is 178.03 kJ/mol.
Answer:
Explanation:
no. of moles of butane = 5.87g / 58.124 = 0.1009mol
since O2 is excess, limiting reagent is butane
from the equation, 2 moles of butane will reacted to produce water = 10 moles
therefore, 0.1009 moles of butane produced water = (0.1009 x 5) = 0.5050 moles
Weight of H2O formed = 0.5050 x 18.015 = 9.10 grams
Answer:
the gravitational force is proportional to the mass of both interacting objects, bigger objects will attract each other with a greater gravitational force. So the mass of either object increases, the force of gravitational attraction between them also increases.
Answer:
292.4 g
Explanation:
- 2Al + 3H₂SO₄ → 3H₂ + Al₂(SO₄)₃
First we <u>convert 53.7 g of Al into moles</u>, using its<em> molar mass</em>:
- 53.7 g ÷ 27 g/mol = 1.99 mol Al
Then we <u>convert Al moles into H₂SO₄ moles</u>, using the <em>stoichiometric coefficients</em>:
- 1.99 mol Al * = 2.98 mol H₂SO₄
Finally we <u>convert 2.98 moles of sulfuric acid into gram</u>s, using its <em>molar mass:</em>
- 2.98 mol H₂SO₄ * 98 g/mol = 292.4 g