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Katena32 [7]
2 years ago
15

Derive, with full working, the symbol equation for the power output P watts of the energy transfer that occurs when a mass of m

kg falls through a height of h metres in t seconds.
Physics
1 answer:
Alexxandr [17]2 years ago
3 0
I agree that the height is kg or an maybe
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(i) 10 m (ii) 20 m (iii) 40 m (iv) 80 m
IRINA_888 [86]

Answer:

20m

420=80m

100

increases

increases then decreases

6 0
3 years ago
An office window has dimensions 3.1 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.954 a
Virty [35]

Answer:

Net forces which pushes the window is 30342.78 N.

Explanation:

Given:

Dimension of the office window.

Length of the window = 3.1 m

Width of the window = 2.1 m

Area of the window = (3.1\times 2.1) = 6.51\ m^2

Difference in air pressure = Inside pressure - Outside pressure

                                           = (1.0-0.954) atm = 0.046 atm

Conversion of the pressure in its SI unit.

⇒  1 atm = 101325 Pa

⇒ 0.046 atm = 0.046\times 101325 =4660.95 Pa

We have to find the net force.

We know,

⇒ Pressure = Force/Area

⇒ Pressure=\frac{Force }{Area}

⇒ Force =Pressure\times Area

⇒ Plugging the values.

⇒ Force =4660.95\times 6.51

⇒ Force=30342.78 Newton (N)

So,

The net forces which pushes the window is 30342.78 N.

3 0
3 years ago
A time-varying horizontal force F(t) = At4 + Bt2 acts for 0.500 s on a 12.25-kg object, starting attime t = 1.00 s. In the SI sy
PSYCHO15rus [73]

Answer:

3.82 Ns

Explanation:

Time varying horizontal Force is given as

F(t) = A t⁴ + B t²

F(t) = 4.50 t⁴ + 8.75 t²

Impulse imparted is given as

I = \int_{0}^{t}Fdt

I = \int_{0}^{1}Fdt

I = \int_{0}^{1}(4.50 t^{4} + 8.75 t^{2})dt

I = ((0.9) (1)^{5} + (2.92) (1)^{3})

I = 3.82 N-s

7 0
3 years ago
Read 2 more answers
Which of the following describes a referee's job?
Serhud [2]

Answer:

C. Supervising the game to make sure teams are playing fairly

5 0
3 years ago
How does Sonar work?i will mark brainliest pls help
Fittoniya [83]
I don't like the wording of any of the choices on the list.

SONAR generates a short pulse of sound, like a 'peep' or a 'ping',
focused in one direction.  If there's a solid object in that direction,
then some of the sound that hits it gets reflected back, toward the
source.  The source listens to hear if any of the sound that it sent
out returns to it.  If it hears its own 'ping' come back, it measures
the time it took for the sound to go out and come back.  That tells
the SONAR equipment that there IS a solid object in that direction,
and also HOW FAR away it is.

RADAR works exactly the same way, except RADAR uses radio waves. 


5 0
3 years ago
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