Like hydrogen fluoride (HF), water (H2O) is a polar covalent molecule.
The electron pair in a non-polar covalent bond is shared equally by the two bonded atoms, but in a polar covalent bond, the electron pair is shared unequally by the two bonded atoms. Differences in electronegativity are what lead to polar bonding.
The entire transfer of valence electron(s) between atoms is referred to as an ionic bond. It is a kind of chemical connection that produces two ions with opposing charges. In ionic bonding, the nonmetal takes the lost electrons to form a negatively charged anion while the metal loses them to become a positively charged cation.
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The current passing through the inductor is 3.8 A. The correct option is D. 3.8 A
<h3>Energy stored in a magnetic field </h3>
From the question, we are to determine the current passing through the inductor.
From the formula, for the energy stored in a magnetic field
E = 1/2LI²
Where E is the energy
L is the inductance
and I is the current
From the given information,
E = 3.6 J
L = 0.50 H
Putting the parameters into the formula, we get
3.6 = 1/2 × 0.50 × I²
3.6 = 0.25 × I²
I² = 3.6 ÷ 0.25
I² = 14.4
I = √14.4
I = 3.7947
I ≅ 3.8 A
Hence, the current passing through the inductor is 3.8 A. The correct option is D. 3.8 A
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Answer:-
2328.454 grams
Explanation:-
Volume V = 18.4 litres
Temperature T = 15 C + 273 = 288 K
Pressure P = 1.5 x 10^ 3 KPa
We know universal Gas constant R = 8.314 L KPa K-1 mol-1
Using the relation PV = nRT
Number of moles of oxygen gas n = PV / RT
Plugging in the values
n = (1.5 x 10^3 KPa ) x ( 18.4 litres ) / ( 8.314 L KPa K-1 mol-1 x 288 K)
n = 11.527 mol
Now the balanced chemical equation for this reaction is
2KNO3 --> 2KNO2 + O2
From the equation we can see that
1 mol of O2 is produced from 2 mol of KNO3.
∴ 11.527 mol of O2 is produced from 2 x 11.527 mol of KNO3.
= 23.054 mol of KNO3
Molar mass of KNO3 = 39 x 1 + 14 x 1 + 16 x 3 = 101 grams / mol
Mass of KNO3 = 23.054 mol x 101 gram / mol
= 2328.454 grams
the average speed is 23.4 km per hour cause it is total distance over total time equal to average speed
