a projectile is fired in the earths gravitational field with a horizontal velocity in v = 9.00m/s. how far does it go in the hor
2 answers:
Answer:
Distance traveled by projectile in horizontal direction will be 4.95 m
Explanation:
We have given horizontal velocity of the projectile v = 9 m/sec
We have to find the distance traveled by projectile in 0.550 sec in horizontal direction.
We know that distance is equal to multiplication of speed and time
So distance traveled in horizontal direction will be equal to
So distance traveled by projectile in horizontal direction will be 4.95 m
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Answer:
The resultant velocity of the plane relative to the ground is;
150 kh/h north
Explanation:
The flight speed of the plane = 210 km/h
The direction of flight of the plane = North
The speed at which the wind is blowing = 60 km/h
The direction of the wind = South
Therefore, representing the speed of the plane and the wind in vector format, we have;
The velocity vector of the plane = 210.
The velocity vector of the wind = -60.
Where, North is taken as the positive y or direction
The resultant velocity vector is found by summation of the two vectors as follows;
Resultant velocity vector = The velocity vector of the plane + The velocity vector of the wind
Resultant velocity vector = 210. + (-60.
) = 210.
- 60.
= 150.
The resultant velocity vector = 150.
Therefore, the resultant velocity of the plane relative to the ground = 150 kh/h north.