The particles vibrate against each other in a soild state........i think
Answer:
About 8.3 minutes
Explanation:
Use the formula for velocity as the distance covered by the light divided the time it takes: ![[tex]velocity=\frac{distance}{time}](https://tex.z-dn.net/?f=%5Btex%5Dvelocity%3D%5Cfrac%7Bdistance%7D%7Btime%7D)
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Use the information about the speed of light in vacuum: 
and the information you are given regarding the distance between Sun and Earth: 
to solve the first velocity equation for the unknown time "t":
we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes
Answer:
Kinetic energy = 127.89 Joules
Explanation:
Kinetic energy is calculated using the following rule:
KE = (1/2)*v* v^2
Where:
m is the mass = 145 g = 0.145 kg
v is the velocity = 42 m/sec
Substitute in the above equation to get the kinetic energy as follows:
KE = (0.5)(0.145)(42)^2
Kinetic energy = 127.89 Joules
Hope this helps :)
This problem can be solved based on the rule of energy conservation, as the energy of the photon covers both the energy needed to overcome the binding energy as well as the energy of ejection.
The rule can be written as follows:
energy of photon = binding energy + kinetic energy of ejectection
(hc) / lambda = E + 0.5 x m x v^2 where:
h is plank's constant = 6.63 x 10^-34 m^2 kg / s
c is the speed of light = 3 x 10^8 m/sec
lambda is the wavelength = 310 nm
E is the required binding energy
m is the mass of photon = 9.11 x 10^-31 kg
v is the velocity = 3.45 x 10^5 m/s
So, as you can see, all the parameters in the equation are given except for E. Substitute to get the required E as follows:
(6.63x10^-34x3x10^8)/(310x10^-9) = E + 0.5(9.11 x 10^-31)(3.45x10^5)^2
E = 6.41 x 10^-16 joule
To get the E in ev, just divide the value in joules by 1.6 x 10^-19
E = 4.009 ev
