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777dan777 [17]
3 years ago
6

A worker is holding a filled gas cylinder still. Which two sentences are true about the energy of the filled gas cylinder?

Physics
2 answers:
ivanzaharov [21]3 years ago
5 0

Answer:

B .It has gravitational potential energy because of its height.

C .Its atoms and molecules have thermal energy.

Explanation:

B. The cylinder has gravitational potential energy; in fact, this is given by

GPE=mgh

where m is the mass of the cylinder, g is the gravitational acceleration and h is the heigth of the cylinder above the ground. Since the height h is different from zero, it means that the GPE is different from zero.

C. The gas inside the cylinder has thermal energy, because its atoms and molecules constantly move (they have a random motion called Brownian motion), and this kind of energy due to the motion of molecules is called thermal energy.

MA_775_DIABLO [31]3 years ago
3 0
The answer is B and C
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Calculate the displacement of the volleyball in sample problem 2f when teh volleyballs final velocity is 1.1 m/s upward
stich3 [128]
We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m

4 0
3 years ago
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nalin [4]
1. make good decisions

2. explosive

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answered these on edge. also, you marked this as physics even though its english. might wanna watch out for that lol, so youll get a quicker answer
8 0
3 years ago
Read 2 more answers
A revolutionary war cannon, with a mass of 2260 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 109 m/s aft
Anton [14]

Answer:

The gain in velocity is 0.37m/s

Explanation:

We need solve this problem though the conservation of momentum. That is,

m_1 v_1 = m_2 v_2

m_1=2260Kg\\m_2=15.5Kg\\v_2= 109m/s

Using the equation to find v_1,

v_1=\frac{m_2 v_2}{m_1}\\v_1=\frac{15.5*109}{2260}\\v_1= 0.7475

Using the conservation of energy equation, we have,

KE= \frac{1}{2}m*v^2

KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J

KE_{cannon}=\frac{1}{2}(2260)(0.7475)^2=631.39J

Total KE= 92077.75+13425530=92708.9J

Now this energy over the cannonball

KE=\frac{1}{2}m*v_2^2

92708.9=\frac{1}{2}15.5v_2^2

V_2 = 109.37m/s

The gain in velocity is 0.37m/s

4 0
3 years ago
2. The length of a day is based on the amount of time that
Serjik [45]

Answer:

the answer is B: earth takes to rotate once on its axis

6 0
3 years ago
The magnitude of the force associated with the gravitational field is constant and has a value FF . A particle is launched from
uysha [10]

Answer:

The kinetic energy of the particle will be 12U₀

Explanation:

Given that,

A particle is launched from point B with an initial velocity and reaches point A having gained U₀ joules of kinetic energy.

Constant force = 12F

According to question,

The kinetic energy is

U_{0}=Fx....(I)

Constant force = 12F

A resistive force field is now set up ,

Resistive force is given by,

F_{r}=12F

When the particle moves from point B to point A then,

We need to calculate the kinetic energy

Using formula for kinetic energy

U=F_{r}x

Put the value of F_{r}

U=12Fx

Now, from equation (I)

U=12U_{0}

Hence, The kinetic energy of the particle will be 12U₀.

7 0
3 years ago
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