Ask question

Ask question

All categories

3 years ago

15

improvements in which area would help reduce the possibility of change to the environment when using uranium as a fuel ?

1 answer:

PilotLPTM [1.2K]3 years ago

5 0

The correct option is MORE EFFICIENT EXTRACTION TECHNIQUES.
Uranium extraction and processing have the potential to impact negative effects on the quality and quantity of surface water and ground water, soil, air quality and biota. Thus, improvement in the area of more efficient extraction will reduce the possibility of change to the environment.

You might be interested in

The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of 13.1

ahrayia [7]

Answer:

The temperature is $T = 168.44 \ K$

Explanation:

From the question ewe are told that

The rate of heat transferred is $P = 13.1 \ W$

The surface area is $A = 1.55 \ m^2$

The emissivity of its surface is $e = 0.287$

Generally, the rate of heat transfer is mathematically represented as

$H = A e \sigma T^{4}$

=> $T = \sqrt[4]{\frac{P}{e* \sigma } }$

where $\sigma$ is the Boltzmann constant with value $\sigma = 5.67*10^{-8} \ W\cdot m^{-2} \cdot K^{-4}.$

substituting value

$T = \sqrt[4]{\frac{13.1}{ 0.287* 5.67 *10^{-8} } }$

$T = 168.44 \ K$

7 0

3 years ago

A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angul

Allisa [31]

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

$KE = \frac{1}{2}Iw^2 +\frac{1}{2} mv^2$

also we know that

$I = \frac{2}{5}mR^2$

$w= \frac{v}{R}$

Now kinetic energy is given by

$KE = \frac{1}{2}(\frac{2}{5}mR^2)w^2 +\frac{1}{2} m(Rw)^2$

$KE = \frac{1}{5}mR^2w^2 +\frac{1}{2} mR^2w^2$

$KE = \frac{7}{10}mR^2w^2$

$KE = \frac{7}{10}*150*(0.200)^2(50)^2$

$KE = 10500 J$

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

7 0

2 years ago

The sun rose at 6:54 this morning.<br>is this an observation or inference?

jeka57 [31]

Observation: You saw/ observed something and you are stating that.

Inference: You are predicting something to be true. If so and so, then this will occur.

4 0

2 years ago

Read 2 more answers

Sean, an astronaut stands on the edge of a lunar crater and throws a Frisbeeâ„˘ horizontally with a velocity of 5.00 m/s. With n

motikmotik

Answer:

48.55mm

Explanation:

4 0

2 years ago

6th grade science I mark as brainliest.

DerKrebs [107]

Answer:

2m 13 $\frac{1}{3}$ s

Explanation:

1.5m = 1s

200m = $\frac{200}{1.5}$ × 1s

= 133 $\frac{1}{3}$ s

= 2m 13 $\frac{1}{3}$ s

3 0

2 years ago