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vampirchik [111]
3 years ago
12

Find the concentration of a solution that is prepared by mixing 15 g of sugar

Chemistry
1 answer:
Naily [24]3 years ago
7 0

Answer: Use the formula x = (c ÷ V) × 100 to convert the concentration (c) and volume (V) of the final solution to a percentage. In the example, c = 60 ml and V = 350 ml.

Explanation: Divide the mass of the solute by the total volume of the solution. Write out the equation C = m/V, where m is the mass of the solute and V is the total volume of the solution. Plug in the values you found for the mass and volume, and divide them to find the concentration of your solution.

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A 40.0 milligram sample of 33p decays to 10.0 milligrams in 50.0 days. What is the half life of 33p?
il63 [147K]

Answer:

half life = 25 days

Explanation:

Given data:

Total amount of sample = 40 mg

Sample left after 50 days = 10 mg

Half life of P³³ = ?

Solution:

<em>1st step:</em>

when time is zero = 40 mg

1 half life = 40/2 = 20 mg

2 half life = 20/ 2= 10 mg

<em>2nd step:</em>

<em>Elapsed time/ half life = HL</em>

half life = 50 days/ 2

half life = 25 days

8 0
3 years ago
Write a chemical equation for nh4+(aq) showing how it is an acid or a base according to the arrhenius definition.
GuDViN [60]

An Arrhenius acid by definition dissociates in water to form H3O+ (or H+) ions while an arrhenius base dissociates in water to form OH- ions.

NH4+(aq) can be categorised as an arrhenius acid since it releases H3O+ ions in aqueous media

NH4+(aq) + H2O (aq) ↔ NH3 (aq) + H3O+(aq)

3 0
3 years ago
Read 2 more answers
Does iron always have a charge of 2+ when it forms an ion
Usimov [2.4K]

Answer:

Roman numeral notation indicates charge of ion when element commonly forms more than one ion. For example, iron(II) has a 2+ charge; iron(III) a 3+ charge.

Explanation:

8 0
3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?
castortr0y [4]

Explanation:

I think the correct answer is B

Hope this helped u

8 0
2 years ago
A certain liquid X has a normal boiling point of 111.20 celsius and a boiling point elevation constant Kb=0.95. calculate the bo
Goshia [24]

Answer: the boiling point is = 137.325°C

Explanation:

From the formula: ∆Tb= Kb*m

From the question, Kb= 0.95, m= 27.5, T1= 111.2°C

Substitute into ∆Tb= Kb*m

∆Tb= 0.95*27.5= 26.125

∆Tb= T2-T1

Hence

T2- 111.2=26.125

T2= 26.125+ 111.2= 137.325°C

8 0
2 years ago
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