To solve this we assume that the hydrogen gas is an
ideal gas. Then, we can use the ideal gas equation which is expressed as PV =
nRT. At a constant pressure and number of moles of the gas the ratio T/V is
equal to some constant. At another set of condition of temperature, the
constant is still the same. Calculations are as follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = (100 + 273.15) K x 2.50 L / (-196 + 273.15) K
<span>V2 = 12.09 L</span>
Therefore, the volume would increase to 12.09 L as the temperature is increased to 100 degrees Celsius.
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Answer:
384.2 K
Explanation:
First we convert 27 °C to K:
- 27 °C + 273.16 = 300.16 K
With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:
Where in this case:
We input the data:
300.16 K * 1600 m³ = T₂ * 1250 m³
And solve for T₂:
T₂ = 384.2 K
Answer : The net ionic equation will be:
![Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)](https://tex.z-dn.net/?f=Ba%5E%7B2%2B%7D%28aq%29%2BSO_4%5E%7B2-%7D%28aq%29%5Crightarrow%20BaSO_4%28s%29)
Explanation :
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced molecular equation will be,
![BaCl_2(aq)+Li_2SO_4(aq)\rightarrow 2LiCl(aq)+BaSO_4(s)](https://tex.z-dn.net/?f=BaCl_2%28aq%29%2BLi_2SO_4%28aq%29%5Crightarrow%202LiCl%28aq%29%2BBaSO_4%28s%29)
The complete ionic equation in separated aqueous solution will be,
![Ba^{2+}(aq)+2Cl^-(aq)+2Li^+(aq)+SO_4^{2-}(aq)\rightarrow 2Li^+(aq)+2Cl^-(aq)+BaSO_4(s)](https://tex.z-dn.net/?f=Ba%5E%7B2%2B%7D%28aq%29%2B2Cl%5E-%28aq%29%2B2Li%5E%2B%28aq%29%2BSO_4%5E%7B2-%7D%28aq%29%5Crightarrow%202Li%5E%2B%28aq%29%2B2Cl%5E-%28aq%29%2BBaSO_4%28s%29)
In this equation the species,
are the spectator ions.
By removing the spectator ions , we get the net ionic equation.
The net ionic equation will be:
![Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)](https://tex.z-dn.net/?f=Ba%5E%7B2%2B%7D%28aq%29%2BSO_4%5E%7B2-%7D%28aq%29%5Crightarrow%20BaSO_4%28s%29)