The mole fraction of solute in a 3.87 m aqueous solution is 0.0697
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calculation</h3>
molality = moles of the solute/Kg of the solvent
3.87 m dissolve in 1 Kg of water= 1000g
find the moles of water= mass/molar mass
that is 1000 g/ 18 g/mol= 55.56 moles
mole of solute = 3.87 moles
mole fraction is = moles of solute/moles of solvent
that is 3.87/ 55.56 = 0.0697
Density is an intrinsic property, so it is independent of the amount of substance present: one gold coin would have the same density as a solid gold boulder.
So if the density of gold is 19.3 g/cm³, the density of a bar of gold and the pieces into which the bar is cut would all be 19.3 g/cm³.
The loss or gain of electrons
Explanation:
The loss or gain of electrons determines if an atom will become a cation or anion.
A cation is a positively charge ion
An anion is a negatively charged ion.
In an atom, we have sub-atomic particles:
Protons are the positively charged particles
Electrons are negatively charged
Neutrons carry no charges
Only electrons can be lost or gained in chemical processes that forms cations and anions.
When a neutral atom gains electron, it has more electrons than protons. This makes it negatively charged and we call it an anion.
When a neutral atom loses an electron, the number of protons is more. We call it a cation.
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In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=

%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%