Answer:
Limitation in the level of possible accuracy of the that can be obtained to mainly whole degrees
Explanation:
The angle measurement values are located around the circularly shaped bevel protractor to which a Vernier scale can be attached to increase the accuracy of the angle measurement reading
The accuracy of the bevel protractor is up to 5 arc minutes or 1/12° with the space on the Vernier scale having graduations of 1/12°, such that two spaces on the main scale is 5 arc minutes more than a space on the Vernier scale and the dimensions of the coincidence of the two scale will have an accuracy of up to 1/12°
Therefore, whereby the Vernier scale is damaged, the accuracy will be limited to the accuracy main scale reading in whole degrees.
Answer:
The exit temperature is 293.74 K.
Explanation:
Given that
At inlet condition(1)
P =80 KPa
V=150 m/s
T=10 C
Exit area is 5 times the inlet area
Now
If consider that density of air is not changing from inlet to exit then by using continuity equation
So
m/s
Now from first law for open system
Here Q=0 and w=0
When air is treating as ideal gas
Noe by putting the values
So the exit temperature is 293.74 K.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a) The required additional minterms for f so that f has eight primary implicants with two literals and no other prime implicant are and
b) The essential prime implicant are and
c) The minimum sum-of-product expression for f are
Explanation:
The explanation is shown on the second third and fourth image
Answer:
106.335 Btu/Ib
Explanation:
Given data :
T1 = 520°R = 288.89K
P1 = 14 Ibf/in^2 = 96526.6 pa
r = 12
k = 1.4
R = 287 J/kg-k
<u>Calculate work done per unit mass of air flowing</u> ( two-stage compressor )
we will apply the equation below
W = 2k / K-1 * ( RT₁ ) *
input values into equation above
W = 247.336 KJ/kg = 106.335 Btu/Ib