Answer:
184 feets
Explanation:
Given the data:
time (sec) __ velocity (ft/sec)
0 __________30
1 __________ 54
2 __________56
3 __________34
4 __________ 8
5 __________ 2
6 __________22
Using left end approximation:
(0,1) ___ f(0) = 30
(1,2) ___ f(1) = 54
(2,3) ___f(2) = 56
(3,4) ___f(3) = 34
(4,5) ___f(4) = 8
(5,6) __ f(5) = 2
Hence, the Total distance traveled during the 6 second interval is:
Change ; dT = 1
1 * (30 + 54 + 56 + 34 + 8 + 2) = 184
Answer:
The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.
Explanation:
Sub to Beast_Building on yt
Cathode Ray Tube i think?
Answer:
a)W=8.333lbf.ft
b)W=0.0107 Btu.
Explanation:
<u>Complete question</u>
The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.
Solution
Preload = F₀=0 lbf
Spring constant k= 200 lbf/in
Initial length of spring x₁=0
Final length of spring x₂= 1 in
At any point, the force during deflection of a spring is given by;
F= F₀× kx where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.
![W=\int\limits^2_1 {} \, Fds \\\\\\W=\int\limits^2_1( {F_0+kx} \,) dx \\\\\\W=\int\limits^a_b {kx} \, dx ; F_0=0\\\\\\W=k\int\limits^2_1 {x} \, dx \\\\\\W=k*\frac{1}{2} (x_2^{2}-x_1^{2} )\\\\\\W=200*\frac{1}{2} (1^2-0)\\\\\\W=100.lbf.in\\\\](https://tex.z-dn.net/?f=W%3D%5Cint%5Climits%5E2_1%20%7B%7D%20%5C%2C%20Fds%20%5C%5C%5C%5C%5C%5CW%3D%5Cint%5Climits%5E2_1%28%20%7BF_0%2Bkx%7D%20%5C%2C%29%20dx%20%5C%5C%5C%5C%5C%5CW%3D%5Cint%5Climits%5Ea_b%20%7Bkx%7D%20%5C%2C%20dx%20%3B%20F_0%3D0%5C%5C%5C%5C%5C%5CW%3Dk%5Cint%5Climits%5E2_1%20%7Bx%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%5C%5CW%3Dk%2A%5Cfrac%7B1%7D%7B2%7D%20%28x_2%5E%7B2%7D-x_1%5E%7B2%7D%20%20%29%5C%5C%5C%5C%5C%5CW%3D200%2A%5Cfrac%7B1%7D%7B2%7D%20%281%5E2-0%29%5C%5C%5C%5C%5C%5CW%3D100.lbf.in%5C%5C%5C%5C)
Change to lbf.ft by dividing the value by 12 because 1ft=12 in
100/12 = 8.333 lbf.ft
work required to compress the spring, W=8.333lbf.ft
The work required to compress the spring in Btu will be;
1 Btu= 778 lbf.ft
?= 8.333 lbf.ft----------------cross multiply
(8.333*1)/ 778 =0.0107 Btu.
Answer:
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Explanation: