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2 years ago

What is horizontal motion

Physics

2 answers:

Stella [2.4K]2 years ago

6 0

Answer:

A projectile moves along its path with a constant horizontal velocity

Klio2033 [76]2 years ago

4 0

Horizontal motion is defined as a projectile motion in a horizontal plane depending upon the force acting on it. For a short distance, the vertical and horizontal components of a projectile are perpendicular and independent of each other.

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List the three ways in which water reaches the atmosphere

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Water cycle, evaporation, condensation, and freezing

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3 years ago

Which of the following describes an action-reaction pair?

Vlad [161]

Answer:

Explanation: LETTER A

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2 years ago

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A microfarad capacitor is charged via a 12v battery. there is 1 kohms resistor in series with the capacitor. how much current is

olga2289 [7]

The answer completely depends on the number that belongs in the space before the word "microfarad".

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3 years ago

The mass of jupiter is 300 times the mass of the earth. Jupiter orbits the sun with Tjupiter = 11.9 yr in an orbit with Rjupiter

mihalych1998 [28]

Answer:

c) 11.9 yr

Explanation:

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By keppler's law we know that

T^2= r^3

T= orbital time period

r= mean distance of the planet from the Sun.

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there, the correct answer will be c= 11.9 yr.

5 0

3 years ago

Four point charges of magnitudes +3q, -q, +2q, and -4q are arranged in the corners of a square of side length L. The charge -q c

mafiozo [28]

Answer:

d) 0 V

Explanation:

It can be showed that the potential due to a point charge q, to a distance d from the charge, can be expressed as follows:

$V = \frac{k*q}{r}$

where k = $\frac{1}{4*\pi*\epsilon0} = 9e9 N*m2/C2$

As the potential is an scalar, and is linear with the charge, we can apply the superposition principle, which means that we can find the potential due to one of the charges, as if the other were not present.

By symmetry, all four charges are at the same distance from the center, so we can write the total potential, as follows:

$V = \frac{k}{d} ( q1 + q2 + q3 + q4) (1)$

where d, is the semi-diagonal of the square, that we can find applying Pythagorean theorem, as follows:

$d = \sqrt{\frac{L^{2}}{4} + \frac{L^{2}}{4} } = L*\frac{\sqrt{2}}{2}$

Replacing by the values in (1) we have:

$V = \frac{9e9N*m2/C2}{\frac{L}{2}*\sqrt{2} }* ( +3q -q + 2q + -4q) = 0 V$

which is equal to the option d).

6 0

3 years ago