Answer:
Torque = –207.4 Nm
Explanation:
Given M = 3.2kg, r = 5.4m, α = –12rad/s² (it is slowing down)
Torque = I × α
α = angular acceleration
I = moment of inertia
I = MR² for a circular hoop
Torque = 3.2×5.4×(– 12)
Torque = –207.4 Nm
Answer:
<em>The friction force has a magnitude of 54 N and points to the left</em>
Explanation:
<u>Friction Force</u>
When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration because the friction force opposes motion.
The friction force when an object is moving on a horizontal surface is calculated by:

Where \mu is the coefficient of static or kinetics friction and N is the normal force.
If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:
N = W
Thus, the friction force is:

The ice skater accelerates a block to the right on frictionless horizontal ice and then stops pushing it. The block continues to move at a constant speed when it finds a sand-covered surface with a kinetic coefficient of friction of 0.36.
The friction force is:
Fr=0.36*150
Fr = 54 N
The friction force has a magnitude of 54 N and points to the left
Answer:
c) cubic centimetre is it's answer..