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kolezko [41]
3 years ago
8

Potential energy is defined as

Physics
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

c

Explanation:

it is stored energy because it is built up in said object

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I will mark brainliest! :D<br> SO please help me M8
Kobotan [32]

Answer: 100 J

Explanation: 1/2 5 x 2^2 = 100

Hope this made any sense.

7 0
3 years ago
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Help me please. I’ll select brainliest!
pishuonlain [190]

Answer:

90 degrees

Explanation:

the answer is 90 because angle a has a square on the angle which means it is 90 degrees

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3 years ago
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The two pucks of equal mass did not move linearly (they came to a stop) after the collision due to the conservation of linear mo
weeeeeb [17]

Compared to the pucks given, the pair of pucks will rotate at the same rate.

Answer: Option A

<u>Explanation:</u>

The law of conservation of the angular momentum expresses that when no outer torque follows upon an article, no difference in angular momentum will happen.  At the point when an item is turning in a shut framework and no outside torques are applied to it, it will have no change in angular momentum.

The conservation of the angular momentum clarifies the angular quickening of an ice skater as she brings her arms and legs near the vertical rotate of revolution.  In the event, that the net torque is zero, at that point angular momentum is steady or saved.  

By twice the mass yet keeping the speeds unaltered, also twice the angular momentum's to the two-puck framework.  Be that as it may, we likewise double the moment of inertia. Since L=I \times \omega, the turning rate of the two-puck framework must stay unaltered.

4 0
3 years ago
What are some of the challenges of scuba diving?
EastWind [94]
Some of the challenges are the unpredictable fish and the risk of scratching againest coral or drowning for not focusing on your oxygen tank.
7 0
3 years ago
Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
salantis [7]

Explanation:

Mass of bumper cars, m_1=m_2=110\ kg

Initial speed of car A, u_1=8\ m/s

Initial speed of car Z, u_2=-10\ m/s

Final speed of car A after the collision, v_1=-10\ m/s

We need to find the velocity of car Z after the collision. Let it is equal to v_2. Using the conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

110\times 8+110\times (-10)=110\times (-10)+110v_2

v_2=\dfrac{-1320}{110}\ m/s

v_2=-12\ m/s

So, the velocity of car Z after the collision is (-12 m/s). Hence, this is the required solution.

5 0
3 years ago
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