Answer:
34545 J
Explanation:
Applying,
E = mc'+cm(t₂-t₁)+Cm(t₂-t₀).............. Equation 1
Where E = Total energy, m = mass of the ice, c' = latent heat of ice, c = specific heat capacity of ice, t₂ = final temperature, t₁ = initial temperature, C = specific heat capacity of water, t₀ = temperature of ice at 0°C
From the question,
Given: m = 35 g = 0.035 kg, t₁ = -10°C, t₂ = 100°C, t₀ = 0°C
Constant: C = 4200 J/kg.K, c = 2100 J/kg.K, c' = 336000 J/kg
Susbtitute these values into equation 1
E = [336000(0.035)]+[0.035×2100(100+10)]+[4200×0.035(100-0)]
E = 11760+8085+14700
E = 34545 J
