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stiv31 [10]
3 years ago
8

Why does hydrochloric acid have a higher boiling point than diatomic fluorine?Why does hydrochloric acid have a higher boiling p

oint than diatomic fluorine?
A.)The stabilizing effect of dipole interactions in hydrochloric acid is high.
B. )Hydrochloric acid is a larger molecule.
C. )Fluorine is a larger molecule.
D. )Hydrochloric acid is polar whereas fluorine is non-polar.
E.)Hydrochloric acid has high intermolecular forces whereas fluorine has low intermolecular forces.
Chemistry
1 answer:
beks73 [17]3 years ago
8 0

Hydrochloric acid is polar which means it has stronger bonds between it's molecules, unlike diatomic fluorine that is non-polar and has weaker bonds. That's why it has a higher boiling point.

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How many grams of sodium metal are needed to make 29.3 grams of sodium chloride? given the reaction: 2na + cl2 → 2nacl?
Bess [88]
2Na + Cl2 → 2NaCl
46 g. ➡️ 117 g
x. ➡️ 29.3 g
x =  \frac{46 \times 29.3}{117}  \\ x = 11.5 \: g
5 0
3 years ago
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Suppose we have a compound that is 4.330 % Li, 22.10 % Cl, 39.89 % O, and 33.69 % H2O. What is the compounds formula?
amid [387]

The  formula   of compound is   LiClO4.3H2O


      <em><u>calculation</u></em>

  • <em><u>  </u></em>find the mole  of  each element

        that is  moles for Li,Cl,O and that of H2O

  • moles = % composition/ molar mass

       For Li = 4.330/ 6.94 g/mol=  0.624 moles

             Cl=22.10/35.5=0.623  moles

           39.89/16 g/mol =2.493  moles

           H20=  33.69/18 g/mol=  1.872  moles

  • find  the mole ratio  by  dividing each moles by smallest number of mole ( 0.624 moles)

        that  is  for  Li= 0.624/0.623=  1

                             Cl= 0.623/0.623=1

                             O = 2.493/0.623 =4

                          H2O= 1.872/0.623=3

<h3>Therefore the formula=LiClO4.3H2O</h3><h3 />
8 0
3 years ago
What volume of a 3.0 M stock solution of H2SO4 is needed to prepare 2.8 L of a 1.6 M H2SO4 solution?
Georgia [21]
Use M1V1 = M2V2 to solve
3(V1) = 2.8 * 1.6
3(V1) = 4.48
V1 = 1.493 L of stock solution
4 0
3 years ago
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Without consulting Appendix B, arrange each group in order of increasing standard molar entropy (S°). Explain.(c) SF₆(g), SF₄(g)
Andre45 [30]

The increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

While, complexity increases from SF₆(g) to S₂F₁₀(g). Therefore, the standard molar entropy of S₂F₁₀(g) is greater than SF₆(g).

Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

learn more about standard molar entropy:

brainly.com/question/15908262

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