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Mariana [72]
3 years ago
5

Which factor has the most significant influence on a liquid's surface tension?

Physics
2 answers:
Setler [38]3 years ago
6 0

Answer:

I think it may be either A. or C.

Explanation:

cestrela7 [59]3 years ago
6 0

Answer: d

Explanation: a p e x

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The pressure inside a sealed container of methane gas (CH4) is 35.0 kPa. If this 80.0 L sample
STatiana [176]

Answer:

<h3>The answer is 30.43 L</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{35000 \times 80}{92000}  =  \frac{2800000}{92000}  =   \frac{700}{23}  \\  = 30.434782...

We have the final answer as

<h3>30.43 L</h3>

Hope this helps you

4 0
3 years ago
A frequency generator sends a 550Hz sound wave through both water and ice. What is the difference in wavelength between the wave
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Answer:

3.1

Explanation:

use formula f = v/lambda

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3 years ago
Function Of The glottis​
Cloud [144]

Answer:

Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.

8 0
3 years ago
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WILL GIVE BRAINLIEST AND 30 POINTS!
frez [133]

Answer:

The answer is 16 and 24

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3 years ago
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A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
Marrrta [24]

Answer:

h = 2.64 meters      

Explanation:

It is given that,

Mass of one ball, m_1=3\ kg

Speed of the first ball, v_1=20\ m/s (upward)

Mass of the other ball, m_2=2\ kg

Speed of the other ball, v_2=-12\ m/s (downward)

We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :

V=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}

V=\dfrac{3\times 20+2\times (-12)}{3+2}

V = 7.2 m/s

Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :

mgh=\dfrac{1}{2}mV^2

h=\dfrac{V^2}{2g}

h=\dfrac{7.2^2}{2\times 9.8}

h = 2.64 meters

So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.

5 0
3 years ago
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