All categories

3 years ago

What is the number of neutrons in Hydrogen, O (A= 1, Z= 1)?

Chemistry

1 answer:

Vilka [71]3 years ago

5 0

Answer:

Explanation:

Hydrogen has 1 proton and one nuetron

Oxygen has 8 protons nad 8 neutrons

You might be interested in

What are some of thr similarties of physical changes and chemical changes?

Marysya12 [62]

The similarities of physical and chemical changes is that both of those changes change the way the object looks by it's physical appearance. Also they use a type of element to change that object.

5 0

3 years ago

Calculate the hydroxide ion concentration [OH-] for a solution with a pH of 6.10

nalin [4]

There are different formula you need to keep in mind when solving for [OH-]

Given that pH = 6.10

pH + pOH = 14

6.10 + pOH = 14

pOH = 7.9

[OH-] = 10^(-pOH)

[OH-] = 10^(-7.9)

[OH-] = 0.000000013

[OH-] = 1.3 x 10^-8

<h2>Answer: [OH-] = 1.3 x 10^-8</h2>

4 0

3 years ago

Why is water said to be universal solvent?

Pachacha [2.7K]

Answer:

Explanation:

And, water is called the "universal solvent" because it dissolves more substances than any other liquid. This allows the water molecule to become attracted to many other different types of molecules.

8 0

3 years ago

Read 2 more answers

Warwick Police discovered the body of a 36-year-old white male (later identified as Darren Davis) in a field about 20 miles nort

lina2011 [118]

I think it was sue to she has all the details to seem like it was her

7 0

3 years ago

Read 2 more answers

How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut

san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = 8 = Concentration in Ethyl acetate / Concentration in water

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

Where X is the amount of material in grams that comes to the organic phase.

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

In the second extraction, you will extract 0.50g of material

Thus, after the two extraction you will lost:

4.44g + 0.50g = 4.94g of material

6 0

3 years ago