Coulomb's law:
Force = (<span>8.99×10⁹ N m² / C²<span>) · (charge₁) · (charge₂) / distance²
= (</span></span><span>8.99×10⁹ N m² / C²<span>) (1 x 10⁻⁶ C) (1 x 10⁻⁶ C) / (1.0 m)²
= (8.99×10⁹ x 1×10⁻¹² / 1.0) N
= 8.99×10⁻³ N
= 0.00899 N repelling.
Notice that there's a lot of information in the question that you don't need.
It's only there to distract you, confuse you, and see whether you know
what to ignore.
-- '4.0 kg masses'; don't need it.
Mass has no effect on the electric force between them.
-- 'frictionless table'; don't need it.
Friction has no effect on the force between them,
only on how they move in response to the force.
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Internal and external combustion engines are two types of heat engines: they convert thermal energy into mechanical energy. The main difference between internal and external combustion engine is that in internal combustion engines, the working fluid burns inside the cylinder, whereas in external combustion engines, combustion takes place outside the cylinder and heat is then transferred to the working fluid.
Answer:
a = 616850.28 m/s²
Explanation:
Given that,
The radius of the neutron star, r = 10 Km
= 10,000 m
The time period of the neutron star, T = 0.8 s
The centripetal acceleration is given by the formula,
a = v²/r
The linear velocity is given by the relation,
v = rω
The time taken to complete one complete rotation is given by the relation
T = 2π /ω
Where,
ω = 2π / T
Substituting v and ω into the equation for centripetal acceleration. It becomes
a = 4π²r/T²
Substituting the given values in the above equation
a = 4π² x 10000 / 0.8²
= 616850.28 m/s²
Hence, the centripetal acceleration of this person is, a = 616850.28 m/s²
