A jumble of relatively young volcanic debris, some of it located where it fell in Mount Hood’s eruptive past, some of it moved here by the colossal advance of the Newton Clark Glacier during the last ice age.
Newton Clark Moraine
As a result, the rocks making up the moraine are sharp and raw, not rounded, and the debris is largely unsorted. Giant boulders perch precariously atop loose rubble, making the moraine one of the most unstable places on the mountain.
Answer:
in your mind yes but the bread is smaller than the earth thus it wouldnt turn the earth into a sandwich.
Answer:
22m/s
Explanation:
Mass, m=60 kg
Force constant, k=1300N/m
Restoring force, Fx=6500 N
Average friction force, f=50 N
Length of barrel, l=5m
y=2.5 m
Initial velocity, u=0
Substitute the values
m
Work done due to friction force
We have
Substitute the values
Initial kinetic energy, Ki=0
Initial gravitational energy, \
Initial elastic potential energy
Final elastic energy,
Final kinetic energy,
Final gravitational energy,
Final gravitational energy,
Using work-energy theorem
Substitute the values
Answer:
Explanation:
The resistance of a conductor is directly proportional to its length and is inversely proportional to its cross-sectional area, this dependence is given by:
is the material's resistance, L is the legth and A is the cross-sectional area.
For the first and second coils, we have:
For the third and fourth coils, we have:
Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A