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3 years ago

Pleaseeeeee helpp....

Chemistry

2 answers:

Elodia [21]3 years ago

6 0

Answer:

Explanation:

Marrrta [24]3 years ago

4 0

Answer:

mass/volume

Explanation:

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Which of the following SI or metric units is a base unit?

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3. Ampere is the base unit for electric current.

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3 years ago

A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce

spin [16.1K]

Explanation:

The given data is as follows.

Volume of lake = $15 \times 10^{6} m^{3}$ = $15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}$

Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = $5.6 \times 15 \times 10^{9} mg$

= $84 \times 10^{9}$ mg

= $84 \times 10^{3}$ kg

Flow rate of river is 50 $m^{3} sec^{-1}$

Volume of water in 1 day = $50 \times 10^{3} \times 86400 liter$

= $432 \times 10^{7}$ liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are $2.9792 \times 10^{10} mg$ or $2.9792 \times 10^{4} kg$

Flow rate of sewage = $0.7 m^{3} sec^{-1}$

Volume of sewage water in 1 day = $6048 \times 10^{4}$ liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = $1.8144 \times 10^{10} mg$ or $1.8144 \times 10^{4}kg$

Therefore, total concentration of lake after 1 day = $\frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l$

= 6.8078 mg/l

$k_{D}$ = 0.2 per day

$L_{o}$ = 6.8078

Hence, $L_{liquid}$ = $L_{o}(1 - e^{-k_{D}t}$

$L_{liquid}$ = $6.8078 (1 - e^{-0.2 \times 1})$

= 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

= 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0

4 years ago

A solid, pure substance containing just carbon and hydrogen is found to contain 35.8g of carbon and 3.72 g of hydrogen. how many

Igoryamba

Answer:

4.36 g of Carbon

Solution:

Step 1: Calculate the %age of Carbon in given Solid as;

Mass of Carbon = 35.8 g

Mass of Hydrogen = 3.72

Total Mass = 35.8 g + 3.72 = 39.52 g

%age of Carbon = (35.8 g ÷ 39.52 g) × 100

%age of carbon = 90.58 %

Step 2: Calculate grams of Carbon in 4.82 g of given solid as;

Mass of Carbon = 4.82 g × (90.58 ÷ 100)

Mass of Carbon = 4.36 g

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3 years ago

why is a molecule of CO2 non polar even though the bonds between the carbon atom and the oxygen atoms are polar

stira [4]

Answer:

Explanation:

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3 years ago

Kaillie was talking and was distracted as she stirred sugar into her tea. when she finally noticed, there was a few crystals of

AleksandrR [38]

Answer:

Supersaturated

Explanation:

The tea has absorbed and dissolved as much sugar as it could. If there is sugar left at the bottom, it means the solution is supersaturated because it can't absorb any more.

5 0

3 years ago

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