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oksian1 [2.3K]
3 years ago
6

How to find the number of protons in an element?​

Chemistry
2 answers:
bixtya [17]3 years ago
8 0

Answer:

To calculate the numbers of subatomic particles in an atom, use its atomic number and mass number: number of protons = atomic number. number of electrons = atomic number. number of neutrons = mass number - atomic number.

Explanation:

i hope it helps and have a great day

Arada [10]3 years ago
5 0

Answer:

Locate the element’s atomic number. The atomic number is located above the element symbol, in the upper left-hand corner of the square. The atomic number will tell you how many protons make up a single atom of an element.

Explanation:

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3 years ago
Maggie is a member of her school’s environmental club and is interested in recycling. She asks the question, “How does exposure
miv72 [106K]
The best describes on why and how Maggie should change her question to make it a better scientific question is that t<span>he question involves giving an opinion about recycling, so it should be changed to rely only on facts. Hope it helps! </span>
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3 years ago
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A hot air balloon is filled with 1.31 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 121 ∘ C . Wha
victus00 [196]

Answer:

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2} (at constant pressure)

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1= 1.31\times 10^6 L\\T_1=11^oC=(11+273.15)K=284.15K\\V_2=?\\T_2=121^oC=(121+273.15)K=394.15 K

Putting values in above equation, we get:

\frac{1.31\times 10^6 L}{284.15 K}=\frac{V_2}{394.14 K}\\\\V_2=\frac{V_1\times T_2}{T_1}

V_2=1.82\times 10^6 L

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

4 0
3 years ago
An aqueous solution containing 100.0 g of nacl and 100.0 g of cacl2 has a volume of 1.00 l and a density of 1.15 g/ml. the vapor
Lemur [1.5K]
Missing question: What is the vapor pressure of the solution at 25°<span>C?
n(NaCl) = 100 g </span>÷ 58,4 g/mol.
n(NaCl) = 1,71 mol. 
NaCl → Na⁺ + Cl⁻, amount of ions are 2 · 1,71 mol = 3,42 mol.
n(CaCl₂) = 100 g ÷ 111 g/mol = 0,9 mol.
CaCl₂ → Ca²⁺ + 2Cl⁻, amount of ions 3 · 0,9 mol = 2,7 mol.
m(solution) = 1000 ml (1,00 L) · 1,15 g/ml = 1150 g.
m(H₂O) = 1150 g - 100 g - 100 g = 950 g.
n(H₂O) = 950 g ÷ 18 g/mol = 118,75 mol.
<span>water's mole fraction = 118,75 mol </span>÷ (118,75 mol + 2,7 mol + 3,42 mol).
water's mole fraction = 0,95.
p(solution) = 0,95 · 23 mmHg = 21,85 mmHg.

6 0
3 years ago
A0.255g sample of antacid was tested and neutralized 23.8mL of 0.1 M HCI. How many ml of acid
CaHeK987 [17]

Answer:

iztsotspysyx

Explanation:

oopcyxlyld

8 0
3 years ago
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