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WITCHER [35]
3 years ago
13

The manufacturer of a 9V dry-cell flashlight battery says that the battery will deliver 20 mA for 80 continuous hours. During th

at time the voltage will drop from 9 V to 6 V. Assume the drop in voltage is linear with time. How much energy does the battery deliver in this 80 h interval
Physics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

17280 J or 17.28 kJ

Explanation:

Given that the voltage drop,

U = U2 - U1

U = 9 - 6

U = 3V

Also, we're told that the current, I is equal to 20 mA with the discharge time, t being 80 hrs.

Converting the time from h oi urs to seconds, we have

t = 80 * 3600

t = 288000

Now, to find the energy needed, we're going to use the formula

w = pt, where p = U * I

p = 3 * 20*10^-3

p = 60*10^-3

w = 60*10^-3 * 288000

w = 17280 J or 17.28 kJ

Therefore, the total energy the battery delivers in the 80 hrs is 17.28 kJ

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An 800 N man climbs 5 m up a ladder. How much gravitational potential energy does he gain?
Artemon [7]

Answer:

4000J

Explanation:

Given parameters:

Weight of the man  = 800N

Height of ladder  = 5m

Unknown:

Gravitational potential energy gained  = ?

Solution:

The gravitational potential energy is due to the position of a body.

 Gravitational potential energy = weight x height

Now insert the parameters;

 Gravitational potential energy  = 800 x 5  = 4000J

5 0
3 years ago
Which example best illustrates kinetic energy?
mihalych1998 [28]

Answer:

A.

Explanation:

In all actuality. The car may not be fully moving but since it's on a hill and the earth moves it makes the most sense. Also since the car is at a slope by the law of motion what goes up must come down so the car is in fact moving.

8 0
3 years ago
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A certain cloud contains 220 water droplets per cubic centimeter. If 1cubic meter = 1,000,000cubic centimeters, how many drops a
lianna [129]
Wouldn't you just have to multiply 220 by 1,000,000? That would mean there are 220,000,000 water droplets in one cubic of the cloud.
3 0
3 years ago
What type of electromagnetic wave can be used to transmit information?
JulijaS [17]
Radio wave only would be the answer.
5 0
3 years ago
Suppose that placing 0.3 inch of lead in front of a gamma source reduces the count rate from 1045 cps to 573 cps. What is um^-1
Ainat [17]

Answer:

14.49 g/cm²

Explanation:

I = Io e^-(ux)

Where:

I = 573

Io = 1045

x = 0.3 inches and

rho = 11.4g/cm^3

Using the conversion constant

1 inch = 2.54 cm;

0.3 inches = 0.3 * 2.54 cm

0.3 inches = 0.762 cm

I/Io = e^-(ux), or say

Io/I = e^(ux), taking the In of both sides

ln(Io/I) = ux, making u subject of formula

u = 1/x * ln(Io/I)

u = 1/0.762 * ln(1045/573)

u = 1.312 * 0.6

u = 0.787

Next, we say that

u/rho = 0.7872/11.4 = 0.069

And finally, we make

1/(u/rho) to be our final answer

Inverse of the answer is = 14.49 g/cm²

Therefore, the um^-1 in g/cm^2? is 14.49

5 0
2 years ago
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