I’m not 100% sure but I think it’s 1098
Answer:
9. Electron Affinity
10. The second option....
Reaction is NH4OH <-> NH4+ OH- (note this is reversible)
Draw up an ICE table
Let x be equilibrium conc of OH- assume init conc of OH is 0M and init conc of NH4+ is 0M also. Init conc of NH4OH is 0.1M so equilibrium conc will be 0.1-x.
%dissociation = x/0.1-x * 100%
1 = 100x/0.1-x
0.1-x = 100x
101x = 0.1
x = 0.0009901
pOH = -log(0.0009901) = 3.00
Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.
Explanation:
Given:
= 0.2 kg,
= 0.15 kg
= 2 m/s,
= 0 m/s,
= ?,
= 1.5 m/s
Formula used is as follows.

where,
v = velocity before collision
v' = velocity after collision
Substitute the values into above formula as follows.

Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.
The Mass of oxygen in isolated sample is 8.6 g
<h3>What is the
Law of Constant composition?</h3>
The law of constant composition states that pure samples of the same compound contain the same element in the same ratio by mass irrespective of the source from which the compound is obtained.
Considering the given ascorbic acid samples:
Laboratory sample contains 1.50 gg of carbon and 2.00 gg of oxygen
mass ratio of oxygen to carbon is 2 : 1.5
Isolated sample will contain 2/1.5 * 6.45 g of oxygen.
Mass of oxygen in isolated sample = 8.6 g
In conclusion, the mass of oxygen is determined from the mass ratio of oxygen and carbon in the compound.
Learn more about the Law of Constant composition at: brainly.com/question/1557481
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Note that the complete question is given below:
A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Another sample of ascorbic acid isolated from citrus fruits contains 6.45 gg of carbon. According to the law of constant composition, how many grams of oxygen does this isolated sample contain?
Express the answer in grams to three significant figures.
8.47 g