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Marianna [84]
3 years ago
14

Which isotope is the most naturally abundant for FluorineThe atomic mass of the isotope is 18.99 am

Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
7 0
Sorry I’m only answering so I could upload
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2 X(9) + Y (9) = 2XY (9)
11Alexandr11 [23.1K]

Answer:

The answer is D. The rate of the forward reaction is greater than the rate of the reverse reaction.

Explanation:

The forward reaction rate was greater than the reverse reaction rate because more product is present at time 2. This is the answer from ap classroom.

8 0
3 years ago
What is the pH of a solution that contains 0.83M HCN (Ka = 4.9x10-10) and 0.64 M potassium cyanide?
oksian1 [2.3K]

Answer:

pH= 9.2

Explanation:

Henderson hasselbach equation

pKa= log Ka= log (4.9 x 10^-10)=9.3

pH=Pka+log \frac{[A-]}{[HA]}

pH=9.3+log \frac{[CN-]}{[HCN]}

pH=9.3+log \frac{[0.64 M]}{[0.83 M]}

pH= 9.2

5 0
3 years ago
element q reacts with dilute acids but not with cold water . element r does not react with dilute acids . element s displaces p
masya89 [10]

Answer:

s<p<q<r

Explanation:

Given

Element s displaces p from its oxide. Thus, s is more reactive that p

p reacts with cold water  but element q cannot react with cold water. Thus,

p is more reactive than q

Element q is able to react with weak or dilute acids but element r in unable to react with weak or dilute acids. Thus, q is more reactive that r

The order of four elements on the basis of their reactivity in descending order is as follows

s<p<q<r

5 0
3 years ago
The electrolysis of molten NaCl is an industrial process. What does the electrolysis produce?
saveliy_v [14]

Answer:

it is D

Explanation:

NaOH and chlorine gas

Electrolysis of Aqueous NaCl Since water can be both oxidized and reduced, it competes with the dissolved Na+ and Cl– ions. Rather than producing sodium, hydrogen is produced. ... The net process is the electrolysis of an aqueous solution of NaCl into industrially useful products sodium hydroxide (NaOH) and chlorine gas.

3 0
3 years ago
If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?
NARA [144]

Answer:

<h3>The answer is 286.36 cm³</h3>

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

V_2 =  \frac{112000 \times 259}{101300}  =  \frac{29008000}{101300}  \\  = 286.3573543...

We have the final answer as

<h3>286.36 cm³</h3>

Hope this helps you

6 0
3 years ago
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