A ball weighing 10 kg traveling at 1.4 m/s hits and rebounds back off a wall and now travels 1.4 m/s in the opposite direction.
1 answer:
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Answer:
was the her position ahead from her window when she caught the object.
Explanation:
Given:
- speed of walking of Henrietta,
- height of projection of projectile,
- Horizontal distance between the window and Henrietta when the projectile was launched:
- Since the projectile was thrown at the time when she had passed below the window 5 seconds ago.
Since the projectile was thrown horizontally therefore the vertical component of velocity is zero.
<u>Now the time taken for the object to reach to Henrietta ignoring the height where she catches:</u>
is the time taken by the projectile to reach Henrietta.
<u>Now the distance further walked by Henrietta in the above time from the point where she was when the projectile was launched:</u>
<u>Now the total horizontal distance from the window to Henrietta when the projectile reached her:</u>
was the her position ahead from her window when she caught the object.
<u>Now the initial horizontal velocity of launch of the projectile:</u>
Answer:
v = 172 km/h
Explanation:
For the first 12 hours, it traveled at an average speed of 185 km/h. Let d₁ is distance. So,
For the next 13 hours, it traveled at an average speed of 160 km/h. Let d₂ is the distance. So,
Average speed = total distance/time taken
So,
So, the average speed of the whole journey is 172 km/h.