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Alex787 [66]
3 years ago
11

An isotope of Uranium, Z = 92 and A = 235, decays by emitting an alpha particle. Calculate the number of neutrons in the nucleus

left behind after the radioactive decay.
Physics
1 answer:
stepan [7]3 years ago
4 0

Answer:

141

Explanation:

The atomic number (Z) corresponds to the number of protons:

Z = p

while the mass number (A) corresponds to the number of protons+neutrons:

A = p + n

So the number of neutrons in a nucleus is equal to the difference between mass number and atomic number:

n = A - Z

For the initial nucleus of Uranium, Z = 92 and A = 235, so the initial number of neutrons is

n = 235 - 92 = 143

An alpha particle carries 2 protons and 2 neutrons: so, when the isotope of Uranium emits an alpha particle, it loses 2 neutrons. Therefore, the number of neutrons after the decay will be

n = 143 - 2 = 141

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Answer :

(1) The density of asphalt is, 1200kg/m^3

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

<u>Part 1 :</u>

As we are given:

Mass of block = 90 kg

Volume of block = 0.075m^3

Formula used :

\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}

Now put all the given values in this formula, we get:

\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3

Thus, the density of asphalt is, 1200kg/m^3

<u>Part 2(a) :</u>

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

<u>Part 2(b) :</u>

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}

2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}

\text{Mass of aluminium}=15.59kg

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

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3 years ago
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