Answer:
U = 1 / r²
Explanation:
In this exercise they do not ask for potential energy giving the expression of force, since these two quantities are related
F = - dU / dr
this derivative is a gradient, that is, a directional derivative, so we must have
dU = - F. dr
the esxresion for strength is
F = B / r³
let's replace
∫ dU = - ∫ B / r³ dr
in this case the force and the displacement are parallel, therefore the scalar product is reduced to the algebraic product
let's evaluate the integrals
U - Uo = -B (- / 2r² + 1 / 2r₀²)
To complete the calculation we must fix the energy at a point, in general the most common choice is to make the potential energy zero (Uo = 0) for when the distance is infinite (r = ∞)
U = B / 2r²
we substitute the value of B = 2
U = 1 / r²
Speed = (wavelength) x (frequency
Speed = (.020 m) x (5 / sec)
Speed = 0.1 m/s
Answer:
Speed of water at the top of fall = 5.40 m/s
Explanation:
We have equation of motion
![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
Here final velocity, v = 26 m/s
a = acceleration due to gravity
![a=9.8m/s^2 \\](https://tex.z-dn.net/?f=a%3D9.8m%2Fs%5E2%20%5C%5C%20)
displacement, s = 33 m
Substituting
![26^2=u^2+2\times 9.8 \times 33\\\\u^2=29.2\\\\u=5.40m/s \\](https://tex.z-dn.net/?f=26%5E2%3Du%5E2%2B2%5Ctimes%209.8%20%5Ctimes%2033%5C%5C%5C%5Cu%5E2%3D29.2%5C%5C%5C%5Cu%3D5.40m%2Fs%20%5C%5C%20)
Speed of water at the top of fall = 5.40 m/s
Answer:
Hey Again!
Your answer is 2450 cm3
!
Explanation:
Volume of cylinder = V=πr2h
2.45L = 2450mL
1mL = 1 cm cubed
2450mL = 2450 cm cubed
*substitute values in*
I HOPE THIS HELPS YOU!!