2 years ago

What type of metals are known as ferromagnetic metals

Physics

1 answer:

Sphinxa [80]2 years ago

4 0

Answer:

those who are attracted to magnets. ex: iron, cobalt and nickel

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A 65-cm segment of conducting wire carries a current of 0.35

algol13

The intensity of the magnetic force exerted on the wire due to the presence of the magnetic field is given by
$F=ILB \sin \theta$
where
I is the current in the wire
L is the length of the wire
B is the magnetic field intensity
$\theta$ is the angle between the direction of the wire and the magnetic field

In our problem, L=65 cm=0.65 m, I=0.35 A and B=1.24 T. The force on the wire is F=0.26 N, therefore we can rearrange the equation to find the sine of the angle:
$\sin \theta= \frac{F}{ILB}= \frac{0.26 N}{(0.35 A)(0.65 m)(1.24 T)}=0.922$

and so, the angle is
$\theta=\arcsin(0.921)=67.1^{\circ}$

6 0

3 years ago

Read 2 more answers

A 5.00-a current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. copper has 8.5 * 1028 free ele

vlada-n [284]

The correct answer is: $3.125*10^{19}$ electrons/second

Explanation:

5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:

Electrons per second = $n_e=\frac{5}{e}=\frac{5}{ 1.60\cdot 10^{-19}}=3.125*10^{19}$