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Gemiola [76]
3 years ago
15

PLEASE HELP SOME1 Smart!

Physics
1 answer:
tester [92]3 years ago
5 0

Answer:

=>. 45°

=>. both angle are equal

=> because it is law of reflection

=> angle of incidence = angle of reflection

hope it helps

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D. they react with oils and fats
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What is the total entropy change if a 0.280 efficiency engine takes 3.78E3 J of heat from a 3.50E2 degC reservoir and exhausts i
babymother [125]

Answer:

\Delta S=1.69J/K

Explanation:

We know,

\eta=1-\frac{T_2}{T_1}=1-\frac{Q_2}{Q_1}      ..............(1)

where,

η = Efficiency of the engine

T₁ = Initial Temperature

T₂ = Final Temperature

Q₁ = Heat available initially

Q₂ = Heat after reaching the temperature T₂

Given:

η =0.280

T₁ = 3.50×10² °C = 350°C = 350+273 = 623K

Q₁ = 3.78 × 10³ J

Substituting the values in the equation (1) we get

0.28=1-\frac{Q_2}{3.78\times 10^{3}}

or

\frac{Q_2}{3.78\times 10^3}=0.72

or

Q_2=3.78\times 10^3\times0.72

⇒ Q_2 =2.721\times 10^3 J

Now,

The entropy change (\Delta S) is given as:

\Delta S=\frac{\Delta Q}{T_1}

or

\Delta S=\frac{Q_1-Q_2}{T_1}

substituting the values in the above equation we get

\Delta S=\frac{3.78\times 10^{3}-2.721\times 10^3 J}{623K}

\Delta S=1.69J/K

7 0
3 years ago
What does letter h mean in physics??​
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4 0
3 years ago
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Answer:5

Explanation:

a=3

b=4

c=√(a²+b²)

c=√9+16

c=√25

c=5

3 0
3 years ago
As the radius of the Gaussian surface increases, the magnitude of the electric field at the surface does which of the followingI
marshall27 [118]

Answer:

Decreases

Explanation:

Gauss's law states that the flux of the electric field through a closed surface is equal to the quotient between the charge inside that surface divided by the permittivity of free space:

\int\limits {E\cdot dS} \,=\frac{Q_{enc}}{\epsilon_0}\\E=\frac{Q_{enc}}{A \epsilon_0}

Therefore, the magnitude of the electric field is inversely proportional to the area, the area is directly proportional to the radius. So, as the radius of the Gaussian surface increases, the magnitude of the electric field at the surface decreases.

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3 years ago
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