Question

a 87 kg block is pulled across the table by the horizontal force of 43N with a fictional force of 7.3 opposing the motion calculate the acceleration of the object

Answer 1

Answer:

a = 0.41 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force [N]

m = mass = 87 [kg]

a = acceleration [m/s²]

The frictional force will be taken as negative, since it opposes the movement of the block.

$43-7.3 = 87*a\\35.7 = 87*a\\a=0.41[m/s^{2} ]$