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Irina-Kira [14]
4 years ago
14

What is the oxidation state of each element in Mn(Cro4)2?

Chemistry
2 answers:
Kobotan [32]4 years ago
8 0

Answer:

CrO4 is the "chromate" ion and has a -2

since there are 2 and the overall charge of Mn(CrO4)2 is zero.. Mn is +4

O is -2 as it usually is...

so Cr is +6

ElenaW [278]4 years ago
7 0

The The oxidation state of each element in Mn(Cro4)2 is

Oxidation state of  Mn is  +4

Oxidation state of  is -2

Oxidation state of Cr is +6

<u>Explanation</u> :

The oxidation number denotes the number of electrons the atom loses in a chemical compound.

Also, oxidation number is equal to the charge of the ion. In the above compound oxidation state of Cro4 is -2 and there are two ions together. Thus, there oxidation state would be -4.

Mn have the oxidation state of +4. And oxidation charge of oxygen is always -2. In equation Cro4 there are 4 oxygen each having oxidation charge of -2. Making it -8 in total. Cro4 has its oxidation charge of -2. Thus adding up the charges it turns out to be +6 for chromium.    

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What do the superscripts and subscripts in the notation ^40 K represent?
raketka [301]

Explanation:

subscript is K

superscript is ^

subscript K means a unit of temperature like F or C

superscript ^ means to the power of

So all together it means to the power of 40 K

3 0
4 years ago
Pick the correct statement for the following isotope: a. 42Ca 42 is the mass number and 20 is the atomic number. b. 42 is the nu
kramer

Answer:

A

Explanation:

To label an element correctly using a combination of the symbol, mass number and atomic number furnishes some important information about the element.

We can obtain these information from the element provided that correct labeling of the element is presented. Firstly, after writing the symbol of the element, the atomic number is placed as a subscript on the left while the mass number of the atomic mass is placed as a superscript on the same left.

Looking at the question asked, we have the element symbol in the correct position as Ca, with 42 also in the correct position which is the mass number. The third number which is 20 is thus the atomic number of the element.

4 0
3 years ago
A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t
kotegsom [21]

<u>Given:</u>

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

<u>To determine:</u>

The enthalpy of formation of AgCl(s)

<u>Explanation:</u>

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol


6 0
3 years ago
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Poh of a solution with a ph of 5.00
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Answer:

9

Explanation:

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8 0
3 years ago
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