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Y_Kistochka [10]
3 years ago
8

This type of severe weather only develops when a group of storms meet over warm tropical waters what type of storm is this

Physics
1 answer:
erastovalidia [21]3 years ago
5 0
Monsoon is the answer
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What is true about colonial families?
MrRissso [65]

Answer:

D

Explanation:

I just took the test and C was wrong, do not listen to that answer. It is "All of the above"

7 0
3 years ago
A car travelled 60 km west in 1.33 h along a straight line, then returned back east for 40 km in 0.67 h. Its average velocity is
Sholpan [36]

Answer:

Option A

Explanation:

Velocity is expressed as distance covered per unit time, with respect to direction. Therefore, v=d/t

Given distance west as 60 km and time as 1.33 then velocity will be

V=60/1.33=45.112781954887 km/h

Rounded off as 45.11 km/h West

Velocity in East will also be given by substituting 40 km for d and 0.67 h for h hence

V=40/0.67=59.701492537313 km/h rounded off as 59.70 km/h East

Taking East as positive then West as negative, the sum of two velocities will be (59.70+-45.11)/2=7.295 km/h East

Approximately 10 km/h East since it is positive

7 0
3 years ago
Some runners have just started a race. They began at rest and are getting faster.What statement best describes the motion of the
olasank [31]

Answer:

B

Explanation:

8 0
3 years ago
How many Faces, Vertices and Edges are there on a cube?
Kay [80]
They have 6 faces
12 edges
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3 0
3 years ago
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The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measur
kogti [31]

Answer:

1280 mg

Explanation:

Radioactive  decay is a phenomenon that occurs when a certain isotope of an element, said to be radioactive, decays, turning into a lighter nucleus and emitting radiation + energy in the process.

The radioactive decay of this isotope of polonium is described by the equation

Q(t)=Q_0 2^{-\frac{t}{140}}

where

Q(t) is the amount of polonium left after time t

Q_0 is the amount of polonium t time t = 0

140 is the half-life of the polonium, in days (it is the time it takes for the initial element to halve its amount)

IN this problem, we know that:

After t = 560 days, the amount of polonium left is Q(t)=80 mg. Therefore, we can re-arrange the equation, substituting t = 560 d, and solve for Q_0 to find the initial amount of polonium:

Q_0 = Q(t) \cdot 2^{\frac{t}{140}}=(80)\cdot 2^{\frac{560}{140}}=1280 mg

5 0
3 years ago
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