Answer:
No
Explanation:
The work that can be turned into heat equals 100% and there is no thermodynamic law that says that cannot be.
Answer:
image is vertical at distance -203.62 cm
magnification is 2.110
Explanation:
given data
n = 1.51
distance u = 96.5 cm
concave radius r1 = 24 cm
convex radius r2 = 19.1 cm
to find out
final image distance and magnification
solution
we will apply here lens formula to find focal length f
1/f = n-1 ( 1/r1 - 1/r2) .......................1
put here all value
1/f = 1.51 -1 ( -1/24 + 1/19.1)
f = 183.43
so from lens formula
1/f = 1/v + 1/u .............................2
put here all value and find v
1/183.43 = 1/v + 1/96.5
so
v = −203.62 cm
so here image is vertical at distance -203.62 cm
and
magnification are = -v /u
magnification = 203.62 / 96.5
magnification is 2.110
Answer:
4 m/s²
Explanation:
Given:
Δx = 60 m
v₀ = 2.0 m/s
v = 22 m/s
Find: a
v² = v₀² + 2aΔx
(22 m/s)² = (2.0 m/s)² + 2a (60 m)
a = 4 m/s²
Answer:
The increase in gravitational potential energy is the same in both cases
Explanation:
It is easier to climb a mountain in a zigzag way rather than climbing on a straight line but since the distance is the same ( vertical height ) , mass and gravity is the same. Hence the increase in gravitational potential energy is the same in both cases.
gravitational potential energy = mgh ( same in both cases )
m = mass
g = acceleration due to gravity
h = distance ( vertical height )
Answer:
Explanation:
At the point when light is vertically polarized is incident on the polarizer whose axes are situated at angle points 
the intensity power in the wake of going through all the polarisers is given by the Malus law, applied threefold for every one of the three axes.
The heading of the direction of the polarization is equivalent to the pivoted axes of the polarizer provided that light is an electromagnetic wave, its course of polarization is therefore controlled by the electric field part.
∴
a)
When sheet A is removed, the transmitted light goes through B, at 30°.
b)
When B is removed, No light passes since the axis of A and the axis of C are perpendicular to each other.
c)
When C is removed, the intensity is indeed zero since the axes are aligned and adjusted at 90° to one another.
