NOTE: The diagram is attached to this solution
Answer:
The acceleration of point A = 14.64 ft/s²
Explanation:
By proper analysis of the diagram, acceleration of point A will be: (Check the free body diagram attached)
![a_{A} = \bar{a} + \frac{\alpha L}{2}](https://tex.z-dn.net/?f=a_%7BA%7D%20%20%3D%20%5Cbar%7Ba%7D%20%2B%20%5Cfrac%7B%5Calpha%20L%7D%7B2%7D)
Weight, W = mg
g = 32.2 ft/s²
m = W/g
![p = m \bar{a}\\p = w \bar{a} /g](https://tex.z-dn.net/?f=p%20%3D%20m%20%5Cbar%7Ba%7D%5C%5Cp%20%3D%20w%20%5Cbar%7Ba%7D%20%2Fg)
![\bar{a} = pg/w\\\bar{a} = 0.25g/2.2\\\bar{a} =3.66](https://tex.z-dn.net/?f=%5Cbar%7Ba%7D%20%3D%20pg%2Fw%5C%5C%5Cbar%7Ba%7D%20%3D%200.25g%2F2.2%5C%5C%5Cbar%7Ba%7D%20%3D3.66)
![\frac{pL}{2} = I \alpha](https://tex.z-dn.net/?f=%5Cfrac%7BpL%7D%7B2%7D%20%3D%20I%20%5Calpha)
but ![I = \frac{wL^{2} }{12g}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BwL%5E%7B2%7D%20%7D%7B12g%7D)
![\frac{pL}{2} = \frac{\alpha wL^{2} }{12g}\\\alpha = \frac{6 g p}{wL}\\\alpha = \frac{6*g*0.25}{2.2L} \\\alpha = 21.96/L](https://tex.z-dn.net/?f=%5Cfrac%7BpL%7D%7B2%7D%20%3D%20%5Cfrac%7B%5Calpha%20wL%5E%7B2%7D%20%7D%7B12g%7D%5C%5C%5Calpha%20%3D%20%5Cfrac%7B6%20g%20p%7D%7BwL%7D%5C%5C%5Calpha%20%3D%20%5Cfrac%7B6%2Ag%2A0.25%7D%7B2.2L%7D%20%5C%5C%5Calpha%20%3D%2021.96%2FL)
![a_{A} = 3.66 + \frac{(21.96/L ) * L}{2}\\a_{A} = 3.66 + 10.98\\a_{A} = 14. 64 ft/s^{2}](https://tex.z-dn.net/?f=a_%7BA%7D%20%20%3D%203.66%20%2B%20%5Cfrac%7B%2821.96%2FL%20%29%20%2A%20L%7D%7B2%7D%5C%5Ca_%7BA%7D%20%20%3D%203.66%20%2B%2010.98%5C%5Ca_%7BA%7D%20%20%3D%2014.%2064%20ft%2Fs%5E%7B2%7D)
Kinetic energy is greatest at the lowest point of a roller coaster and least at the highest point
Answer:
The electron has a negative charge and is found outside of the nucleus.
Explanation:
1.) Neutrons have no charge, not a negative charge.
2.) Neutrons are found inside the nucleus, not outside.
3.) Protons have a positive charge.