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lisabon 2012 [21]
2 years ago
8

How many moles of carbon atoms is 7.72 x 10 ^24 atoms of carbon? Round to 2 decimal places

Chemistry
1 answer:
soldier1979 [14.2K]2 years ago
5 0

Answer:

<h2>12.82 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.72  \times {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 12.8 239

We have the final answer as

<h3>12.82 moles</h3>

Hope this helps you

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Describe the contributions made by Oparin, Haldane, Miller, and Urey toward understanding the origin of organic molecules.
balu736 [363]

Answer:

The theory of Oparin and Haldane was based on the fact that the primitive atmosphere was very different from the current atmosphere, since energy was abundant on the young planet. Both proposed that the appearance of life was preceded by a period they called "chemical evolution."

On the other hand, Miller Urey made an experiment where it was shown that some organic components were formed spontaneously if they were simulating the conditions of the Earth's early atmosphere.

Explanation:

The first hypotheses about the origin of life on Earth were suggested by Oparin and Haldane, who worked independently. Oparin presented his ideas on the origin of life in the year of 1922 by publishing them in the year of 1924. For his part, Haldane published similar ideas in 1929, however, Haldane gave priority to Oparin in the formulation of the theory.

Oparin based his hypotheses using a model he called "coacervates", which are colloidal systems formed by macromolecules that formed in aqueous media and would have evolved to form cells with membranes. According to Oparin, living beings modified the primitive atmosphere and this would have prevented, the formation of life from inorganic substances.

The Miller and Urey experiments helped reinforce the theory that the first way of life was created spontaneously through chemical reactions. However, there are still many scientists who are not convinced.

8 0
3 years ago
2 KClO_2 produces 2 KCl+ 3O_2 when heated. If this reaction produces 82.8 g of KCl how many grams of O2 were produced?
Ad libitum [116K]

Answer:

37.046 grams of oxygen gas were produced.

Explanation:

2KClO_2\rightarrow 2KCl+ 3O_2

Moles of potassium chlorite = \frac{82.2 g}{106.5 g/mol}=0.7718 mol

According to reaction 2 moles of potassium chlorite gives 3 moles of oxygen gas.

Then 0.7718 moles of potassium chlorite will give:

\frac{3}{2}\times 0.7718 mol=1.1577 mol of oxygen gas.

Mass of 1.1577 moles of oxygen gas:

1.1577 mol × 32 g/mol = 37.046 g

37.046 grams of oxygen gas were produced.

4 0
3 years ago
Calculate the number of moles in a 2.98 g sample of aluminum.
Ksju [112]
Molar mass <span>Aluminium ( Al) = 26.98 g/mol

1 mole ------------ 26.98 g
? mole ----------- 2.98 g

moles Al = 2.98 x 1 / 26.98

moles Al = 2.98 / 26.98

= 0.110 moles

hope this helps!

</span>
3 0
2 years ago
What is the answer???
igomit [66]
The bowl has more volume, the bearing has more volume. The mass is bigger for the bearing because it is heavier than the bowl. It is made of metal and the weight of it is greater than the bowl.(the body shape).
7 0
3 years ago
The normal freezing point of a certain liquid
stepladder [879]

Answer : The molal freezing point depression constant of X is 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of X liquid (solvent) = 450.0 g

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}\times 1000}{\text{Molar mass of urea}\times \text{Mass of X liquid}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X= 0.4^oC

i = Van't Hoff factor = 1  (for non-electrolyte)

K_f = molal freezing point depression constant of X = ?

m = molality

Now put all the given values in this formula, we get

[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}

k_f=4.12^oC/m

Therefore, the molal freezing point depression constant of X is 4.12^oC/m

4 0
3 years ago
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