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3 years ago

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Type of introduction

1 answer:

AlladinOne [14]3 years ago

8 0

Answer:

Five Types of Introductions.

“Inquisitive” Explain why your subject is important, curious, or interesting.

“Paradoxical” Explain what aspects of your subject seem improbable. ...

“Corrective” Explain how your subject has been misunderstood or misrepresented by others. ...

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A 5.0-mL sample of CO2 gas is enclosed in a gas-tight

Neporo4naja [7]

Answer:

3.5ML

Explanation:

4 0

3 years ago

The overall force on an object is called the:

shusha [124]

Answer: D

Explanation:

Balanced force is when 2 equal forces are acting on each other, summing force isn’t a thing, unbalanced force is when 2 unequal forces are acting on each other, and net force is the total amount of forces acting on an object. Hope this helps!

8 0

4 years ago

Read 2 more answers

In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?

dedylja [7]

<u>Answer:</u> The correct answer is $2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)$

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

<u>Reaction 1:</u> $2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

<u>Reaction 2:</u> $CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

<u>Reaction 3:</u> $HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

<u>Reaction 4:</u> $2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

<u>Reaction 5:</u> $SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is $2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)$

6 0

3 years ago

H2 + CaCl2 --> 2HCl + Ca How many grams of HCl are made when 2.93 g of<br><br> Ca are made?

Sholpan [36]

Answer:

H2 + CaCl2 -> 2HCl + Ca

How many grams of HCl are made when 2.93 g of

Ca are made?

Explanation:

From the given balanced chemical equation, it is clear that:

2mol. of HCl and 1mol. of Ca are produced.

2mol. of HCl weighs --- 73.0g

1mol. of Ca weighs --- 40.0g

Hence,

73.0g of HCl and 40.0g of Ca are produced.

When 2.93g of Ca is produced then, how many grams of HCl will be produced?

$=> 2.93g Ca * \frac{73.0g HCl}{40.0g Ca} \\=5.35g HCl$

Hence, 5.35g of HCl is formed.

4 0

3 years ago

What is the ph at the half-stoichiometric point for the titration of 0.22 m hno2(aq) with 0.1 m koh(aq)? for hno2, ka = 4.3x10-4

vazorg [7]

Given that Ka = 4.3 × 10^-4
At the half equivalence (Stoichiometric) point;
pH = pKa = - log (Ka)
Therefore; pKa = - log (4.3 ×10^-4)
= 3.37
Therefore; the pH at the half-stoichiometric point is 3.37

6 0

3 years ago

Read 2 more answers