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9966 [12]
3 years ago
10

Type of introduction ​

Chemistry
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

Five Types of Introductions.

“Inquisitive” Explain why your subject is important, curious, or interesting.

“Paradoxical” Explain what aspects of your subject seem improbable. ...

“Corrective” Explain how your subject has been misunderstood or misrepresented by others. ...

You might be interested in
How does fermentation allow the cell to continue to make atp when oxygen is not present?
kap26 [50]

Explanation:

Usually most cells that carry anaerobic respiration utilize the Glycolysis pathway because it does not require oxygen. It is also believed it is the ancient metabolic pathway by utilized by primordial cells  when the earth's atmosphere was not mainly oxygen,  

Glycolysis consumes 2 ATPs (during the conversion of Glucose to Fructose 1,6 bisphosphate ) but produces a gross $ ATPs. It, therefore, has a net ATP of 2. This is inefficient when compared to the Krebs cycle that utilizes oxygen to produce 34 ATPs. Anaerobic respiration produces pyruvate. This pyruvate is broken down into an organic acid like lactic acid which is excreted from the cell, which is why fermented food tastes sour.

Learn More:

For more on Glycolysis metabolic pathway check out;

brainly.com/question/211200

brainly.com/question/1966268

#LearnWithBrainly

5 0
3 years ago
Calculate the rms speed of an oxygen gas molecule, o2, at 17.0 ∘c .
ludmilkaskok [199]
The  RMS  of O2  at  17  degrees   is  calculated  as  follows

RMs= ( 3RT/m)^1/2   where

R= ideal  gas   constant  =  8.314
T=   temperature=   17+273=  290 K
M=  molar  mass   in  KG =   32/1000=  0.032  Kg

Rms  is  therefore= sqrt (3x   8.314  x290/0.032 )  =  sqrt( 226036.875

RMs=475.43

6 0
3 years ago
Read 2 more answers
Beverly and Carl are in a race. Their graphs show the data.
Nikitich [7]

Given the data, the correct statement is

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

<h3>What is acceleration? </h3>

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

  • a is the acceleration
  • v is the final velocity
  • u is the initial velocity
  • t is the time

<h3>How to determine the initial acceleration of Beverly</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 15 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (15 – 0) / 10

a₁ = 1.5 m/s²

<h3>How to determine the final acceleration of Beverly</h3>
  • Initial velocity (u) = 15 m/s
  • Final velocity (v) = 35 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (35 – 15) / 40

a₂ = 0.5 m/s²

<h3>How to determine the initial acceleration of Carl</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 10 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (10 – 0) / 10

a₁ = 1 m/s²

<h3>How to determine the final acceleration of Carl</h3>
  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 30 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (30 – 10) / 40

a₂ = 0.5 m/s²

SUMMARY

  • Initial acceleration of Beverly = 1.5 m/s²
  • Final acceleration of Beverly = 0.5 m/s²
  • Initial acceleration of Carl = 1 m/s²
  • Final acceleration of Carl = 0.5 m/s²

From the above calculations, we can see that Beverly's initial acceleration is higher than that of Carl's and their final acceleration is the same.

Therefore, the correct answer to the question is:

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

Complete question

See attached photo

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

8 0
2 years ago
If 18 mL of methanol is used to make an aqueous solution that is 15% methanol by volume, how many mL of solution is produced?
Yuri [45]

Answer:

120.0 mL.

Explanation:

  • As it is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

We suppose that the initial W% of methanol is 100.0 %

<em>∴ (W%V) before dilution = (W%V) after dilution.</em>

W% before dilution = 100.0 %, V before dilution = 18.0 mL.

W% after dilution = 15.0 %, V after dilution = ??? mL.

<em>∴ V after dilution = (W%V) before dilution/W% after dilution = </em>(100.0 %)(18.0 mL)/(15.0%)<em> = 120.0 mL.</em>

7 0
3 years ago
Pls help will give brainlest​
Vinvika [58]

that's right.............:)

5 0
3 years ago
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