The answer is 2.0, and it is because
I will assume that the sign ? between the C and the CCH3 is a triple bond, and I will represent it by three vertical lines |||
So the reaction is:
<span>CH3CH2CH2CH2C ||| CCH3+2Br2 ---->
This is a typical reaction known as halogenation of alkines.
This is an addition reaction, i.e. the alkyne undergoes an addition of the Br2 (and it also happens with Cl2) to the triple bond to form a tetra halide.
.
Br Br
</span> | |
<span><span>CH3CH2CH2CH2C ||| CCH3+2Br2 ----> CH3 CH2 CH2 CH2 C - C</span> - CH3
| |
Br Br
</span>
Answer: Volume im pretty sure
For the purpose we will here use the ideal gas law:
p×V=n×R×T
V= ?
n = 0.5 moleT= 273.15 K (at STP)
p= 101.325 kPa (at STP)
R is universal gas constant, and its value is 8.314 J/mol×K
Now when we have all necessary date we can calculate the number of moles:
V=nxRxT/p
V=0.5x8.314x273.15/101.325= 11.2 L = 11200 mL
Answer: D.
