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Dima020 [189]
3 years ago
7

Jupiter has approximately 100 times the volume of earth? True False

Physics
2 answers:
Daniel [21]3 years ago
8 0
The answer is false.
seropon [69]3 years ago
6 0
False this is incorrect because Jupiter is 1,300 the volume of earth. 
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A car accelerates uniformly at 2m/s2 for 3minutes. what is the velocity of the car​
grigory [225]

Answer:

56.7 nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

4 0
4 years ago
A football is kicked into the air from an initial height of 4 feet. The height, in feet, of the football above the ground is giv
kakasveta [241]

Answer: 0.5 seconds or 2.625 seconds

Explanation:

At t = 0, The ball is 4 ft above the ground.

The height of the football varies with time in the following way:

s(t) = -16 t² + 50 t + 4

we need to find the time in which the height would of the football would be 25 ft:

⇒25 = -16 t² + 50 t + 4

we need to solve the quadratic equation:

⇒ 16 t² - 50 t + 21 = 0

t = \frac{50 \pm \sqrt{50^2-4\times 16\times 21}}{2\times16}

⇒ t = 0.5 s or 2.625 s

Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.

3 0
3 years ago
Read 2 more answers
Nick, a 60 kg physics student, wants to go bungee jumping, but doesn't have a bungee cord. He finds a 15 m long, strong spring (
vitfil [10]

Answer:

h = 24.81 m

Explanation:

Given:-

- The mass of the student, m = 60 kg

- The length of the spring, L = 15 m

- The spring constant, k = 60 N/m

Find:-

How far below the bridge is he hanging

Solution:-

- First realize that after the student attempts a bungee jump he oscillates violently ( dynamic motion ). After some time all the kinetic energy has been converted to Elastic and gravitational potential energy student is (stationary) and hanging down on one end of the spring.

- We will apply equilibrium condition on the student. We see that there are two forces acting on the student. The weight (W) of the student acting downward is in combat with the spring restoring force (Fs) acting upwards.

- Apply equilibrium condition in vertical direction:

                               Fs - W = 0

                               Fs = W

- The weight and spring force can be expressed as:

                               k*x = m*g

Where,     g : Gravitational acceleration constant = 9.81 m/s^2

                x : The extension of the spring from original position

- Solve for the extension (x) of the spring for this condition.

                              x = m*g / k

- Plug in the values and evaluate:

                              x = (60 kg)*(9.81 m/s^2) / (60 N/m)

                              x = 9.81 m

- The spring extends for about 9.81 m from its original length. So the distance (h) from edge of the bridge would be:

                              h = L + x

                              h = 15 + 9.81

                              h = 24.81 m

4 0
3 years ago
Determine the ratio of the resistivity of pure water to silver?
kondor19780726 [428]

Answer:

3 \cdot 10^{11} : 1

Explanation:

Silver is a generally excellent conductor, this implies its resistivity is low (from table, we can check the exact worth i.e \rho_s = 1.6 \cdot 10^{-8} \Omega m)

Pure water, rather, is an extremely awful conductor, this implies its resistivity is exceptionally high, of order of k \Omega \cdot m (10^3 \Omega m )

Indeed, even without knowing the exact estimation of the pure water resistivity, we can appraise the proportion between the pure water resistivity and the silver resistivity by looking at the two orders of magnitude:

r= \frac{10^3 \Omega m}{10^{-8} \Omega m}  \sim 10^{11}

Therefore, we can say that the correct answer is

3 \cdot 10^{11} : 1

4 0
3 years ago
At what condition does a body become weightless at equator
salantis [7]
Hope this is helpful <span>Weightlessness

</span>
3 0
4 years ago
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