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3 years ago

What patterns in the rock layer fossils helped you identify an extinction?

2 answers:

7 0

You can often tell by disturbances in the fossils bones. Maybe like dust or particles symbolize harm or mass extinction in a prehistoric animal or maybe even new fossils like some animals that went extinct recently like 200 years.

Lilit [14]3 years ago

3 0

Answer:

Hope this helps!! :D

Explanation:

Often, the rock layers bookending the mass extinction are noticeably different in their compositions. These changes in the rocks show the effects of environmental disturbances that triggered the mass extinction and sometimes hint at the catastrophic cause of the extinction.

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A student mixed 100 mL of water at 15°C with 100 mL of water at 65°C. What is the final temperature of the water?

horrorfan [7]

Answer:

50°C

Explanation:

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7 0

3 years ago

For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data: ΔH∘rxn 180.5 kJ/mol ΔS∘

nasty-shy [4]

Answer:

7.28 × 10³ K

Explanation:

Let's consider the following reaction.

N₂(g) + O₂(g) → 2 NO(g)

The reaction is spontaneous when the standard Gibbs free energy (ΔG°) is negative. ΔG° is related to the standard enthalpy of the reaction (ΔH°) and the standard entropy of the reaction (ΔS°) through the following expression.

ΔG° = ΔH° - T . ΔS°

If ΔG° < 0,

ΔH° - T . ΔS° < 0

ΔH° < T . ΔS°

T > ΔH°/ΔS° = (180.5 × 10³ J/mol)/(24.8 J/mol.K) = 7.28 × 10³ K

The reaction is spontaneous above 7.28 × 10³ K.

7 0

4 years ago

A crime lab received a 235-gram sample. The sample had a molecular mass of 128.1 grams and the empirical formula is CH2O. How ma

kvv77 [185]

Explanation:

Given parameters:

Mass of sample = 235g

Molecular mass of sample = 128.1g

Empirical formula = CH₂O

Unknown:

Mass of each element in the sample = ?

Solution:

To solve this problem, we must know that the empirical formula of any compound is the simplest ratio of the atoms it contains. This is not the true formula of the compound.

Molecular formula = (Empirical formula)ₙ

Let us find the molecular mass of the sample;

CH₂O = 12 + 2(1) + 16 = 30g

128.1 = (30)n

n = 4

The molecular formula of the compound is; (CH₂O)₄ = C₄H₈O₄

Now to find the grams of each element in the sample;

Express the molecular mass of each element and that of the compound as a fraction and multiply with the given mass;

For C;

$\frac{4 x 12}{128.1} x 235\\$ = 88.06g