Answer:
<em>Bromine </em><em>atom </em><em>would </em><em>have </em><em>smallest </em><em>radius.</em>
Explanation:
<h3>Comparison between Bromine and Iodine</h3>
As we know that on ascending down the group the size of atom increases as a new shell is added on ascending by one step... so Iodine has a greater size than Bromine.
<h3>Comparison between Bromine and Bromine ion</h3>
As bromine is a halogen atom, so it's ionisation enthalpy is the most in it's period.. so it cannot loose an electron to form a Br+ cation.. so it forms a Br- anion.. by accepting a. electron, so as 1 electron is added to the shell.. the electrons have increased than the no. of protons, so the size would increase as the protons now have to hold more electrons than before, so attraction would decrease. A second reason can also be mentioned as when an electron is added to an atom, it experiences some repulsion from other electrons in same energy shell, so the size would increase. Screening effect of the mid shell electrons also contribute in increasing the size of atom. So Bromine ion would have a greater size than Bromine atom.
<em>By </em><em>the </em><em>same </em><em>analogy </em><em>the </em><em>iodine </em><em>ion </em><em>would </em><em>also </em><em>have </em><em>grater </em><em>size </em><em>than </em><em>the </em><em>iodine </em><em>atom</em><em>,</em><em> </em><em>it </em><em>also </em><em>becomes </em><em>greater </em><em>in </em><em>size </em><em>than </em><em>the </em><em>bromine </em><em>atom.</em><em>.</em>
<em>THUS </em><em>THE </em><em>BROMINE </em><em>ATOM </em><em>HAS </em><em>THE </em><em>LEAST </em><em>RANKING </em><em>WHEN </em><em>ARRANGED </em><em>IN </em><em>DECREASING </em><em>SIZE </em><em>OF </em><em>GIVEN </em><em>SPECIES!</em><em>!</em><em>!</em>