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GaryK [48]
2 years ago
13

Which of the following has the smallest radius?

Chemistry
2 answers:
ivanzaharov [21]2 years ago
4 0

Answer:

<em>Bromine </em><em>atom </em><em>would </em><em>have </em><em>smallest </em><em>radius.</em>

Explanation:

<h3>Comparison between Bromine and Iodine</h3>

As we know that on ascending down the group the size of atom increases as a new shell is added on ascending by one step... so Iodine has a greater size than Bromine.

<h3>Comparison between Bromine and Bromine ion</h3>

As bromine is a halogen atom, so it's ionisation enthalpy is the most in it's period.. so it cannot loose an electron to form a Br+ cation.. so it forms a Br- anion.. by accepting a. electron, so as 1 electron is added to the shell.. the electrons have increased than the no. of protons, so the size would increase as the protons now have to hold more electrons than before, so attraction would decrease. A second reason can also be mentioned as when an electron is added to an atom, it experiences some repulsion from other electrons in same energy shell, so the size would increase. Screening effect of the mid shell electrons also contribute in increasing the size of atom. So Bromine ion would have a greater size than Bromine atom.

<em>By </em><em>the </em><em>same </em><em>analogy </em><em>the </em><em>iodine </em><em>ion </em><em>would </em><em>also </em><em>have </em><em>grater </em><em>size </em><em>than </em><em>the </em><em>iodine </em><em>atom</em><em>,</em><em> </em><em>it </em><em>also </em><em>becomes </em><em>greater </em><em>in </em><em>size </em><em>than </em><em>the </em><em>bromine </em><em>atom.</em><em>.</em>

<em>THUS </em><em>THE </em><em>BROMINE </em><em>ATOM </em><em>HAS </em><em>THE </em><em>LEAST </em><em>RANKING </em><em>WHEN </em><em>ARRANGED </em><em>IN </em><em>DECREASING </em><em>SIZE </em><em>OF </em><em>GIVEN </em><em>SPECIES!</em><em>!</em><em>!</em>

Salsk061 [2.6K]2 years ago
3 0
A has the smallest radius
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Salt is often added to water to raise the boiling point to heat food more quickly. if you add 30.0g of salt to 3.75kg of water,
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Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

<h3>What is the boiling-point elevation?</h3>

Boiling-point elevation describes the phenomenon that the boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.

  • Step 1: Calculate the molality of the solution.

We will use the definition of molality.

b = mass solute / molar mass solute × kg solvent

b = 30.0 g / (58.44 g/mol) × 3.75 kg = 0.137 m

  • Step 2: Calculate the boiling-point elevation.

We will use the following expression.

ΔT = Kb × m × i

ΔT = 0.512 °C/m × 0.137 m × 2 = 0.140 °C

where

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  • Kb is the ebullioscopic constant.
  • b is the molality.
  • i is the Van't Hoff factor (i = 2 for NaCl).

The normal boiling-point for water is 100 °C. The boiling-point of the solution will be:

100 °C + 0.140 °C = 100.14 °C

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

Learn more about boiling-point elevation here: brainly.com/question/4206205

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