How can an electric current produce a magnetic field

Physics

2 answers:

anygoal [31]3 years ago

8 0

Answer:

When the compass is placed below the wire, and the electric current switched on, the needle deflects in the opposite direction. If an electric current is passed through a long coil of wire (a solenoid ) a magnetic field is produced which is the same shape as that of a bar magnet.

Explanation:

diamong [38]3 years ago

6 0

Answer:

a changing electric field creates a magnetic field.

Explanation:

if you have a circuit and you send AC current through (AC = Alternating current) so that the electrons move back and forth, they will create a changing electric field.

This produces a magnetic field (because that's what the universe does).

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At a point P located some distance away from two charges, the electric potential created by the first charge is 5V. The electric

vaieri [72.5K]

Answer:

e. 7V

Explanation:

If the potential created at the point P by the first charge is 5 V, and the electric potential created by the second charge is 2 V, as the potential is proportional to the electric field created by the charges, which is linear (due to it is directly proportional to the value of the charges), we can apply the superposition principle.

In this way, we can calculate the total potential, at a point P, as the algebraic sum of the potentials created by all the charges, as if the other ones were not present.

In this case, we have:

V = V₁ + V₂ = 5 V + 2 V = 7 V

6 0

4 years ago

What will a spring scale read for the weight of a 58.0-kg woman in an elevator that moves in free fall?

solniwko [45]

Answer:

0 N

Explanation:

The elevator is under free fall. So, when a body is under free fall, the acceleration is only due to gravity. So, the acceleration of the elevator or the woman inside it, is acceleration due to gravity in the downward direction.

The spring scale gives the value of the normal force acting on the woman and doesn't give the exact weight of the woman. Under normal conditions, when the spring scale is at rest, then the upward normal force equals the weight and hence weight of a body is equal to the normal force acting on the body.

But, here, the body is not at rest. Weight\tex](mg)[/tex] acts in the downward direction and normal force $(N)$ acts in the upward direction. The woman is moving down with acceleration equal to acceleration due to gravity $(g)$