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3 years ago

How can an electric current produce a magnetic field

Physics

2 answers:

anygoal [31]3 years ago

8 0

Answer:

When the compass is placed below the wire, and the electric current switched on, the needle deflects in the opposite direction. If an electric current is passed through a long coil of wire (a solenoid ) a magnetic field is produced which is the same shape as that of a bar magnet.

Explanation:

diamong [38]3 years ago

6 0

Answer:

a changing electric field creates a magnetic field.

Explanation:

if you have a circuit and you send AC current through (AC = Alternating current) so that the electrons move back and forth, they will create a changing electric field.

This produces a magnetic field (because that's what the universe does).

You might be interested in

Which statement is true?

vladimir2022 [97]

a.current varies throughout a parallel circuit.

Hope this helps!

8 0

3 years ago

Which is not a factor that affects the pressure of a gas in a closed container?

maksim [4K]

it is size of of particles because it does not matter about the size in a closed container

7 0

3 years ago

The Celsius temperature of –273° C is termed “absolute zero” and is the initial value on the metric unit of temperature, the Kel

Kazeer [188]

Answer:

273 Kelvin

Explanation:

If -273 Celsius is 0 Kelvin, then 273 Kelvin will be 0 Celsius.

7 0

3 years ago

With the same block-spring system from above, imagine doubling the displacement of the block to start the motion. By what factor

Fofino [41]

Answer:

A) K / K₀ = 4 b) v / v₀ = 4

Explanation:

A) For this exercise we can use the conservation of mechanical energy

in the problem it indicates that the displacement was doubled (x = 2xo)

starting point. At the position of maximum displacement

Em₀ = Ke = ½ k (2x₀)²

final point. In the equilibrium position

$Em_{f}$ = K = ½ m v²

Em₀ = Em_{f}

½ k 4 x₀² = K

(½ K x₀²) = K₀

K = 4 K₀

K / K₀ = 4

B) the speed value

½ k 4 x₀² = ½ m v²

v = 4 (k / m) x₀

if we call

v₀ = k / m x₀

v = 4 v₀

v / v₀ = 4

3 0

3 years ago

Two stones are launched from the top of a tall building. One stoneis thrown in a direction 30.0^\circ above the horizontal with

Butoxors [25]

Answer:

Part A)

t(1) > t(2), the stone thrown 30 above the horizontal spends more time in the air.

Part B)

x(f1) > x(f2), the first stone will land farther away from the building.

Explanation:

Part A)

Let's use the parabolic motion equation to solve it. Let's define the variables:

y(i) is the initial height, it is a constant.
y(f) is the final height, in our case is 0
v(i) is the initial velocity (v(i)=16 m/s)
θ1 is the first angle, 30°
θ2 is the first angle, -30°

For the first stone

$y_{f1}=y_{i1}+v*sin(\theta_{1})t_{1}-0.5gt_{1}^{2}$

$0=y_{i1}+16*sin(30)t_{1}-0.5*9.81*t_{1}^{2}$

$0=y_{i1}+8t_{1}-4.905*t_{1}^{2}$ (1)

For the second stone

$0=y_{i2}+16*sin(-30)t_{2}-4.905t_{2}^{2}$

$0=y_{i2}-8t_{2}-4.905t_{2}^{2}$ (2)

If we solve the equation (1) we will have:

$t_{1}=\frac{-8\pm \sqrt{64+19.62*y_{i}}}{-9.81}$

We can do the same procedure for the equation (2)

$t_{1}=\frac{8\pm \sqrt{64+19.62*y_{i}}}{-9.81}$

We can analyze each solution to see which one spends more time in the air.

It is easy to see that the value inside the square root of each equation is always greater than 8, assuming that the height of the building is > 0. Now, to get positive values of t(1) and t(2) we need to take the negative option of the square root.

Therefore, t(1) > t(2), it means that the stone thrown 30 above the horizontal spends more time in the air.

Part B)

We can use the equation of the horizontal position here.

First stone

$x_{f1}=x_{i1}+vcos(30)t_{1}$