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3 years ago

Describe how you would make 1.0 l of a supersaturated solution of cdi2

1 answer:

3 0

(Missing in the question) solubility in g per 100 mL of water:
CdI2 86.2 (cold water) so,
-We will heat a saturation solution of CdI2 [86.2 g / 100 mL], by the effect of the heat the solution will be unsaturated and dissolve more CdI2 when reaching a high temperature. and let the solution cools again by itself and covers it well to make sure there is no dust in it. when it reaches back to the cold water temperature, we will find the solution is supersaturated and all the solute will stay dissolved.

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What is the resulting formula unit when magnesium and nitrogen bond

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The answer is Mg3N2.

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3 years ago

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How much force is needed to accelerate a 1000-kg car at a rate of 3 m/s2? a 1003 N b 0.003 N c 3000 N d 333.3 N

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Answer:

Option c.

Explanation:

According to Newton's law, formula to solve this problem is:

F = m . a

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a → 3 m/s²

F = 1000 kg . 3m/s² → 3000 N

1 N = 1 kg . m/s² according to SI, Internation System of units.

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3 years ago

1) on combustion, 1 mole of an alkane gives 2 moles of carbon dioxide and 3 moles of water. Suggest the molecular formula of thi

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1 mole of an alkane gives 2 moles is correct answer

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4 years ago

A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af

larisa86 [58]

Explanation:

The given reaction is as follows.

$HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)$

Hence, number of moles of NaOH are as follows.

n = $0.05 L \times 0.1 M$

= 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

n = $0.025 L \times 0.1 M$

= 0.0025 mol

According to ICE table,

$HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)$

Initial: 0.005 mol 0.0025 mol 0 0

Change: -0.0025 mol -0.0025 mol +0.0025 mol

Equibm: 0.0025 mol 0 0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

[HA] = $\frac{0.0025 mol}{V}$

[NaA] = $\frac{0.0025 mol}{V}$

$[A^{-}] = [NaA] = \frac{0.0025 mol}{V}$

Now, we will calculate the $pK_{a}$ value as follows.

pH = $pK_{a} + log \frac{A^{-}}{HA}$

$pK_{a} = pH - log \frac{[A^{-}]}{[HA]}$

= $3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}$

= 3.42

Thus, we can conclude that $pK_{a}$ of the weak acid is 3.42.

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3 years ago

Describe what it means for something to be an acid.

Oduvanchick [21]

A sour-tasting material (usually in a solution) that dissolves metals and other materials. Technically, a material that produces positive ions in solution. An acid<span> is the opposite of a base and has a pH of 0 to 7.</span>

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4 years ago

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