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3 years ago

The table below lists norm al and abnormal events. Explain why some events would never happen normally.

Chemistry

1 answer:

vlada-n [284]3 years ago

5 0

Beacause of lack of force in all three scenarios.
In scenario one there’s two forces acting in the bottle atmospheric pressure and gravity.Gravity keeps the ball at the lowest pointwithout force resisting it.
Umber two there’s no other force greater than gravity that would cause movement to the apple..
And number three there are isn’t any force acting in the rubber band greater than the elastic force to make it stretch
Hope this helps and mark as brainliest if you thought it was most helpful :)

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Which law relates to the ideal gas law?

professor190 [17]

Answer: The law that related the ideal gas law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Explanation:

There are 4 laws of gases:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

Mathematically,

$P_1V_1=P_2V_2$

Charles' Law: This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

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$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Gay-Lussac Law: This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

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$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Avogadro's Law: This law states that volume is directly proportional to number of moles at constant temperature and pressure.

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$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Hence, the law that related the ideal gas law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$

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3 years ago

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In which situation are unbalanced forces acting on an object?(1 point)

Alex Ar [27]

Answer:

1. Two people stand on the same side of a large tire. Both people pull the tire with equal force.

2. an object’s ability to not change its motion

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A sample of pure oxalic acid (H2C2O4.2H2O) weighs 0.2000 g and requires 30.12 ml of KOH solution for

ValentinkaMS [17]

The molarity of KOH is 0.1055 M

calculation

Step 1: write the equation for reaction between H₂C₂O₄.2H₂O and KOH

H₂C₂O₄.2H₂O + 2 KOH → K₂C₂O₄ +4 H₂O

step 2: find the moles of H₂C₂O₄.2H₂O

moles = mass÷ molar mass

from periodic table the molar mass H₂C₂O₄.2H₂O= (1 x2) +(12 x2) +(16 x4) + 2(18)=126 g/mol

= 0.2000 g ÷ 126 g/mol =0.00159 moles

step 3: use the mole ratio to calculate the moles of KOH

H₂C₂O₄.2H₂O : KOH is 1:2

therefore the moles of KOH =0.00159 x 2 = 0.00318 moles

step 4: find molarity of KOH

molarity = moles/volume in liters

volume in liters = 30.12/1000=0.03012 L

molarity is therefore = 0.00318/0.03012 =0.1055 M

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