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Naily [24]
3 years ago
12

HELP DUE SOON

Engineering
2 answers:
Free_Kalibri [48]3 years ago
5 0
I think it’s A

Correct me if I’m wrong.
Fudgin [204]3 years ago
5 0
I am sure it’s A hope it’s right
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please answer correctly if it is not correct, report it to them thank you for answering correctly.god bless you​
Sergio [31]
1 is c 2 d 3 a 4 b5is I do
8 0
3 years ago
Read 2 more answers
For laminar flow over a flat plate, the local heat transfer coefficient hx is known to vary as x−1/2, where x is the distance fr
Reika [66]

Answer:

2

Explanation:

So for solving this problem we need the local heat transfer coefficient at distance x,

h_x=cx^{-1/2}

We integrate between 0 to x for obtain the value of the coefficient, so\bar{h}_x =\frac{1}{x} \int\limit^x_0 h_x dx\\\bar{h}_x = \frac{c}{x} \int\limit^x_0 \frac{1}{\sqrt{x}}dx\\\bar{h}_x = \frac{c}{c} (2x^{1/2})\\\bar{h}_x = 2cx^{-1/2}

Substituing

\bar{h}_x=2h_x\\\frac{\bar{h}_x}{h_X}=2

The ratio of the average convection heat transfer coefficient over the entire length is 2

6 0
4 years ago
10. True or False? A disruptive technology<br> radically changes the way people live and<br> work.
Anettt [7]

Answer:

<u>True</u>

Explanation:

According to Investopedia.com, "Disruptive technology is an innovation that significantly alters the way that consumers, industries, or businesses operate".

So yes, a disruptive does radically change the way people live and work.

5 0
3 years ago
Read 2 more answers
In c the square root of a number N can be approximated by repeated calculation using the formula NG = 0.5(LG + N/LG) where NG st
DanielleElmas [232]

Answer:

Following are the program to the given question:

#include <stdio.h>//header file

double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters

{

double NG, LG = initialGuess,diff;//defining double variable

while(1)//use loop to calculate square root value

{

NG = 0.5 * (LG + N / LG);//using given formula

diff = NG - LG;//calculating difference

if(diff < 0)//use if to check difference is less than 0

diff = -diff;//decreaing difference

if(diff < 0.005)//use if that check difference is less than 0.005

break;//using break keyword  

else//defining else block

{

LG = NG;//holding value

}

}

return NG;//return value

}

int main()//defining main method

{

double ans, n,initialguess = 1.0;//defining double variable

n = 4;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 120.5;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 36.01;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 0.25;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

printf("\nEnter a number: ");//print message

scanf("%lf", &n);//input value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

}

Output:

Please find the attachment file.

Explanation:

  • In this code, a method "square_root" is declared that takes two variable "N, initialGuess" in its parameters, inside the method a three double variable is declared.
  • It uses the given formula and uses the diff variable to hold its value and uses two if to check its value is less than 0 and 0.005 and return its calculated value.
  • In the main method, three double variables are declared that use the "n" to hold value and "ans" to call the method that holds its value and print its value.

8 0
3 years ago
Given x = 67 and y = 18, use two's complement to calculate:(1)x+y (2) x-y (3)-x+y (4)-x-y. Do the calculation, show the results
joja [24]

Answer:

See attachment

Explanation:

8 0
3 years ago
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