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3 years ago

what is the cost to run a single 100 w light bulb for 30 days if the electric company charges $0.18 for every KW-hr?

Physics

1 answer:

xxTIMURxx [149]3 years ago

8 0

Explanation:

power of the bulb = 100w=0.1kw

power consumption when the bulb is used for 30 days ( 30 *24 = 720 hours) =0.1*720=72kwh

cost to run the bulb for 30 days = 72*0.18

= $12.96

Answer is $12.96..................

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Explanation:

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4 years ago

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In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-[q_2+q_3]$

$m_1\times c_1\times (T_f-T_1)=-[m_2\times c_2\times (T_f-T_2)+m_3\times c_3\times (T_f-T_2)]$

where,

$c_1$ = specific heat of unknown sample = ?

$c_2$ = specific heat of water = $4186J/kg^oC$

$c_3$ = specific heat of copper = $390J/kg^oC$

$m_1$ = mass of unknown sample = 72.0 g = 0.072 kg

$m_2$ = mass of water = 203 g = 0.203 kg

$m_2$ = mass of copper = 187 g = 0.187 kg

$T_f$ = final temperature of calorimeter = $39.4^oC$

$T_1$ = initial temperature of unknown sample = $80.0^oC$

$T_2$ = initial temperature of water and copper = $11.0^oC$

Now put all the given values in the above formula, we get

$0.072kg\times c_1\times (39.4-80.0)^oC=-[(0.203kg\times 4186J/kg^oC\times (39.4-11.0)^oC)+(0.187kg\times 390J/kg^oC\times (39.4-11.0)^oC)]$

$c_1=8748.78J/kg^oC$

Therefore, the specific heat of unknown sample is, $8748.78J/kg^oC$

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3 years ago

what is the cost to run a single 100 w light bulb for 30 days if the electric company charges $0.18 for every KW-hr?​

what is the cost to run a single 100 w light bulb for 30 days if the electric company charges $0.18 for every KW-hr?