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3 years ago

How old do u have to be to be considered that u died of old age?

Physics

1 answer:

Jlenok [28]3 years ago

6 0

Answer:

Average around 75

Explanation:

It's the average age. You don't really always die of old age but it is 75 years of age.

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A star is estimated to be 4.8 x 10^15 kilometers away from the earth. When we see this star in the night sky, how old is this im

Veseljchak [2.6K]

Answer:

B. 500 years

Explanation:

The light coming from the star and reaching us on the Earth travels with uniform motion (with constant velocity), so we can use the equation of uniform motion which relates distance covered, speed and time taken:

$v=\frac{d}{t}$

where

v is the speed

d is the distance covered

t is the time taken

In this problem:

$v=3.00\cdot 10^8 m/s$ is the speed at which light travels

$d=4.8\cdot 10^{15} km = 4.8\cdot 10^{18}m$ is the distance that light has to cover from the star to the Earth

Therefore, by rearranging the equation, we can find the time:

$t=\frac{d}{v}=\frac{4.8\cdot 10^{18}}{3.00\cdot 10^8}=1.6\cdot 10^{10}s$

And by converting into years, this time is

$t=\frac{1.6\cdot 10^{10}}{(365)(24)(60)(60)}=507 y$

So, approximately 500 years: this means that the image we see of the star is 500 years old.

4 0

3 years ago

Read 2 more answers

What is the magnitude of a point charge that would create an electric field of 1.18 N/C at points 0.822 m away?

katrin [286]

Answer:

q = 8.85 x 10⁻¹¹ C

Explanation:

given,

Electric field, E = 1.18 N/C

distance, r = 0.822 m

Charge magnitude = ?

using formula of electric field.

$E = \dfrac{kq}{r^2}$

k is the coulomb constant

$q= \dfrac{Er^2}{k}$

$q= \dfrac{1.18\times 0.822^2}{9\times 10^9}$

q = 8.85 x 10⁻¹¹ C

The magnitude of charge is equal to q = 8.85 x 10⁻¹¹ C

4 0

3 years ago

If the diameter of each of a car's wheels is 0.4 meters, approximately, what was the average speed of the car for its three-hour

Reptile [31]

Answer:

42 km/h was the average speed of the car for its three-hour trip.

Explanation:

Diameter of the car wheel = d = 0.4 m

Radius of the car wheel = r = 0.5 d = 0.5 × 0.4 m =0.2 m

Distance covered in 1 complete revolution = $2\pi r$

Distance covered in 100,000 complete revolution,D = $2\pi r\times 100,000$

$D=2\times 3.14\times 0.2 m\times 100,000=125,663.71 m$

1 m = 0.001 km

125,663.71 m = 125,663.71 × 0.001 km = 125.66371 km

Time taken to complete 100,000 revolution by a wheel = t = 3 hours

Speed of car : S

$S=\frac{125.66371 km}{3hours}=41.89 km/h\approx 42 km/h$

42 km/h was the average speed of the car for its three-hour trip.

8 0

3 years ago

Read 2 more answers

A) At a certain instant, a particle-like object is acted on by a force F = (3.0 N) ihat - (3.0 N) jhat + (9.0 N) khat while the

Paha777 [63]

Answer:

a) Instantaneous rate at which the force does work on the object = -6 W

b) $\texttt{Velocity of object,}\vec{v}=4\hat{j}$

Explanation:

a) Given that

$\vec{F}=3\hat{i}-3\hat{j}$

and

$\vec{v}=-2\hat{i}+4\hat{k}$

Instantaneous rate at which the force does work on the object is called power.

Power is the dot product of force and velocity.

$P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).(-2\hat{i}+4\hat{k})=-6W$

Instantaneous rate at which the force does work on the object = -6 W

b) Here given that $\vec{v}=-a\hat{j}$

Power = -12 W

$P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).a\hat{j}=-12W\\\\-3a=-12\\\\a=4\\\\\vec{v}=4\hat{j}$

$\texttt{Velocity of object,}\vec{v}=4\hat{j}$

4 0

3 years ago

What is the magnitude of the force that is exerted on a 20 kg mass to give it an acceleration of 10.0

ANEK [815]

Answer:Mass of the body = 20 kg.

Final Velocity = 5.8 m/s.

Initial velocity = 0

Time = 3 seconds.

Using the Formula,

Acceleration = (v - u)/ t

= (5.8 - 0)/ 3

= 1.6 m /s².

Now, Using the Formula,

Force = mass × acceleration

= 20 × 1.6

Explanation: I REALLY HOPE THIS HELPS I'M KINDA NEW AT THIS :] :]

8 0

2 years ago