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amm1812
3 years ago
15

Sand and GravelA. element B. compoundC. homogeneous solution D. heterogeneous ​

Chemistry
1 answer:
RoseWind [281]3 years ago
7 0

Answer:

D.heterogeneous.....

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Nitrogen is 5 valence electrons
oxygen is 6 valence electrons
fluorine is 7 electrons
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3 years ago
If you try to place the compound on the pan over the flame, what could possibly happen? Explain your answer. [2 marks] anyone pl
Scilla [17]

Answer:

it will probably flame up or explode or maybe start boiling

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Ion Formed of Cl , Te
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Why is the water cycle called a cycle and not a system?
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5 0
4 years ago
A standard lanthanum solution is prepared by dissolving 0.1968 grams of lanthanum oxide (La2O3) in excess nitric acid and diluti
sweet-ann [11.9K]

Answer:

1.208x10⁻³M and 392.5ppm La(NO3)3

Explanation:

The reaction that occurs is:

La2O3 + 6HNO3 → 2La(NO3)3 + 3H2O

Molarity is defined as the moles of solute (In this case, LaO3) per liter of solution. And ppm, are mg of solute per liter of solution.

To solve this question we must find the moles of La(NO3)3 produced and its mass in milligrams to find molarity and ppm:

<em>Moles La2O3 -Molar mass: 325.81g/mol-</em>

0.1968g * (1mol / 325.81g) = 6.04x10⁻⁴ moles La2O3

<em>Moles La(NO3)3:</em>

6.04x10⁻⁴ moles La2O3 * (2mol La(NO3)3 / 1mol La2O3) = 1.208x10⁻³ moles La(NO3)3

<em>Molarity:</em>

1.208x10⁻³ moles La(NO3)3 / 1L =

<h3>1.208x10⁻³M</h3>

<em>Mass La(NO3)3 -Molar mass: 324.92g/mol-</em>

1.208x10⁻³ moles La(NO3)3 * (324.92g / mol) = 0.392.5g La(NO3)3

In mg:

392.5mg La(NO3)3 / 1L =

392.5ppm La(NO3)3

7 0
3 years ago
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