Answer:
The final position is 36 feet.
Explanation:
initial position, d = 330 feet
speed, v = 3 feet per minute
time, t = 30 minute
now the time is 32 minute
time interval = 2 minute
So, the distance in 2 minutes is
d' = 2 x 3 = 6 feet
So, the final position is
D = 30 + 6 = 36 feet
stand with your knees bent to absorb the impact, like a skydiver. Theoretically, your legs would flex as you and the elevator touched down, spreading your body's deceleration over a longer period (impact force is proportional to speed and mass, and inversely proportional to time and stopping distance the longer the time spent stopping, the less the force). The effectiveness of this approach at high speeds, however, remains unclear, and research shows that you would likely be subjecting your knees and legs to greater injury risk at low speeds. This approach also keeps your body parallel to the lines of force, which increases the chance of bone breakage as you crumple to the floor under high load.
Hope this helps have a good day.....
b. is equally as toxic as carbon monoxide (CO).
Explanation:
Hydrogen Cyanide is a product of combustion that is equally as toxic as carbon monoxide CO.
The gas is a product of combustion in blast furnances, coke ovens, e.t.c
- Just like carbon monoxide, they are blood agents that are toxic in the body
- Prolonged exposure to hydrogen cyanide can lead to death eventually.
- The gas is a able to produce cyanide ion that seriously impacts the process of cellular respiration and bringing it to a halt.
- It is listed as one of the dangerous chemical weapons.
Learn more:
Safety data sheets brainly.com/question/2188622
#learnwithBrainly
The solution would be like
this for this specific problem:
<span>
The force on m is:</span>
<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:</span>
<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2
Since the Ms are the same, then
2mx^2 / L^2 = m(L - x)^2 / L^2
2x^2 = (L - x)^2
xsqrt2 = L - x
x(1 + sqrt2) = L
x = L / (sqrt2 + 1) From here, we rationalize.
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1)
x = L(sqrt2 - 1) / (2 - 1)
x = L(sqrt2 - 1) </span>
= 0.414L
<span>Therefore, the third particle should be located the 0.414L x
axis so that the magnitude of the gravitational force on both particle 1 and
particle 2 doubles.</span>
